Answer:
Part 1) ![IJ=2.3\ units](https://tex.z-dn.net/?f=IJ%3D2.3%5C%20units)
Part 2) ![HJ=12\ units](https://tex.z-dn.net/?f=HJ%3D12%5C%20units)
Part 3) ![HJ=0.75\ units](https://tex.z-dn.net/?f=HJ%3D0.75%5C%20units)
Part 4) ![IH=4.7\ units](https://tex.z-dn.net/?f=IH%3D4.7%5C%20units)
Step-by-step explanation:
Part 1) HI = 3.9 and HJ = 6.2. Find IJ
we have that
I is between H and J
![HJ=HI+IJ](https://tex.z-dn.net/?f=HJ%3DHI%2BIJ)
substitute the given values and solve for IJ
![6.2=3.9+IJ](https://tex.z-dn.net/?f=6.2%3D3.9%2BIJ)
subtract 3.9 both sides
![6.2-3.9=IJ](https://tex.z-dn.net/?f=6.2-3.9%3DIJ)
![2.3=IJ](https://tex.z-dn.net/?f=2.3%3DIJ)
Rewrite
![IJ=2.3\ units](https://tex.z-dn.net/?f=IJ%3D2.3%5C%20units)
Part 2) JI = 25 and HI = 13. Find HJ
we have that
H is between I and J
![IJ=IH+HJ](https://tex.z-dn.net/?f=IJ%3DIH%2BHJ)
remember that
IH=HI and IJ=JI
substitute the given values and solve for HJ
![25=13+HJ](https://tex.z-dn.net/?f=25%3D13%2BHJ)
subtract 13 both sides
![25-13=HJ](https://tex.z-dn.net/?f=25-13%3DHJ)
![12=HJ](https://tex.z-dn.net/?f=12%3DHJ)
Rewrite
![HJ=12\ units](https://tex.z-dn.net/?f=HJ%3D12%5C%20units)
Part 3) H is the midpoint of IJ and IH = 0.75. Find HJ
we have that
H is between I and J and H is the midpoint of IJ
so
![IJ=IH+HJ](https://tex.z-dn.net/?f=IJ%3DIH%2BHJ)
----> because H is the midpoint
we have
![IH=0.75\ units](https://tex.z-dn.net/?f=IH%3D0.75%5C%20units)
therefore
![HJ=0.75\ units](https://tex.z-dn.net/?f=HJ%3D0.75%5C%20units)
Part 4) H is the midpoint of IJ and IJ = 9.4. Find IH
we have that
H is between I and J and H is the midpoint of IJ
so
-----> equation A
----> equation B
substitute equation B in equation A
![IJ=2(IH)](https://tex.z-dn.net/?f=IJ%3D2%28IH%29)
substitute the given value and solve for IH
![9.4=2(IH)](https://tex.z-dn.net/?f=9.4%3D2%28IH%29)
Divide by 2 both sides
![IH=4.7\ units](https://tex.z-dn.net/?f=IH%3D4.7%5C%20units)
Answer:
i cant see the photo its messy or is it just me
Step-by-step explanation:
Let's go:
8)
Total of senior students = 38
Total of senior students that preferred evening classes: 7
7/38 = aproximately 0,18 or 18%
Alternative A)
9)
Imagine being sold 100 desserts. Of these 100 desserts, 75% até chocolate, meaning 75 of these desserts are chocolate. Of these 75, 23% contains nuts. So:
75 × 0,23 = 17,25 = aproximately 17,3%
Alternative C)
I hope I helped you.
Lisa wrote the number in the
hundreds place
Glad I could help, and good luck!
AnonymousGiantsFan
Answer:
s = 17 units
Step-by-step explanation:
In triangle ABD,
(AB)² + (BD)² = (AD)² (by Pythagoras Theorem)
=> 8² + 15² = s²
=> 64 + 225 = s²
=> s = ![\sqrt{289}](https://tex.z-dn.net/?f=%5Csqrt%7B289%7D)
=> s = 17 units
Hope it helps :)
Please mark my answer as the brainliest