Answer:

![\sqrt[3]{0.95} \approx 0.9833](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.95%7D%20%5Capprox%200.9833)
![\sqrt[3]{1.1} \approx 1.0333](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1.1%7D%20%5Capprox%201.0333)
Step-by-step explanation:
Given the function: ![g(x)=\sqrt[3]{1+x}](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7B1%2Bx%7D)
We are to determine the linear approximation of the function g(x) at a = 0.
Linear Approximating Polynomial,
a=0
![g(0)=\sqrt[3]{1+0}=1](https://tex.z-dn.net/?f=g%280%29%3D%5Csqrt%5B3%5D%7B1%2B0%7D%3D1)

Therefore:

(b)![\sqrt[3]{0.95}= \sqrt[3]{1-0.05}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.95%7D%3D%20%5Csqrt%5B3%5D%7B1-0.05%7D)
When x = - 0.05

![\sqrt[3]{0.95} \approx 0.9833](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.95%7D%20%5Capprox%200.9833)
(c)
(b)![\sqrt[3]{1.1}= \sqrt[3]{1+0.1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1.1%7D%3D%20%5Csqrt%5B3%5D%7B1%2B0.1%7D)
When x = 0.1

![\sqrt[3]{1.1} \approx 1.0333](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1.1%7D%20%5Capprox%201.0333)
Answer: 12
Step-by-step explanation:
We have to check which of PEMDAS rules can be applied in this case. We have only ADDITION. In this case we can observe that addition is:
1. Associative

2. Commutative

3. has Additive property
Answer:
X=5
Step-by-step explanation:
the sum has to equal 180 because its a linear pair,
10×5=50
26×5=130
triangle on right is the same as the triangle on the left
use pythagorean theorem
hypotenuse will give to the sides of the rectangle
a^2 + b^2 = hypotenuse squared
10.4^2 = 108.16
15.3^2 = 234.09
342.25 = hypotenuse squared
take the square root in both sides
hypotenuse = the square root of 342.25 =
18.5
add up the areas of the 2 triangles and rectangle
triangle area is 1/2 times 10.4 times 15.3 =
79.56
2 triangles areas are 159.12
rectangle area is 18.5 × 7 = 129.5
159.12 + 129.5 = 288.62
answer 1 = 288.62
second question:
to get 1 side take the
square root of 702.25 which is
26.5
to get the perimeter
multiply 26.5 by 4 which is
106
answer 2 is choice B 106