Answer:
a=30 , b = 0
Step-by-step explanation:
let the two numbers be represented as a and b
a + b = 30... eqn 1
a - b = 30 ...... eqn 2
we then add the two equations to get values for a and b
a + b + a - b = 30 + 30
a + b + a -b = 60
2a = 60 ( diivide both sides by 2)
a = 30
we then put value for a = 30 into any of the equations to get b
a + b = 30, 30 + b= 30
b = 30 -30 , b = 0
to confirm if the answers are correct, we insert the values for a and b in the two equations.
a + b = 30..... eqn 1, 30 + 0 = 30
a - b = 30 ...... eqn 2 , 30 - 0 = 30
Answer:
750 units
Step-by-step explanation:
As given in question,
speed of solution = 30 mL/hr
1 L of solution contains heparin = 25000 units
=> 1000 mL of solution contains heparin = 25000 units
= 25 units
Hence, 30 mL of solutions contains heparin = 30 x 1 mL of solution contains heparin
= 30 x 25
= 750 units
Hence, heparin administered per hour = 750 units
Answer:
C -3, -2 ,2, 4
Step-by-step explanation:
The range is the output values, or the y values
-3, -2 ,2, 4 are the output values
Answer:
The solution should be log7^3(49)-1/3log7(49)=1/3*2
B-2/3
