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3 years ago

5

Work out the value of 4⁵ I think it 1024

2 answers:

Varvara68 [4.7K]3 years ago

8 0

Answer:

4^5 = 1024

Step-by-step explanation:

Write down the # on the left (4) by the # of times on the left (5)

So it would be: 4x4x4x4x4 = ?

You can cut this problem into pieces.

1. 4x4 = 16

2. 4x4 = 16

3. 16x16 = 256 <em>(use standard multiplication method)</em>

4. 256 x 4 = 1024

<em>I hope this helps:)</em>

vovikov84 [41]3 years ago

4 0

Answer:

1024

Step-by-step explanation:

yeah it's 1024 lol

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The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the expect

Liula [17]

Answer:

After 25 years the population will be:

Australia: 22271200
China: 1580220878
Mexico: 157380127
Zaire: 112794819

Step-by-step explanation:

Growth rate problem that has a growth rate proportional to the population size can be solved using the equation:

P(t) = P₀eʳᵗ

t is your unit of time. It could be days, or hours, or minutes. It changes depending on each problem. In this problem, t is measured in years because you're jumping from 2000 to 2025. Years just makes the most sense to measure that leap in time.

P(t) is the population at time t. An example in this problem could be P(20) would be the population 20 years after the initial count. or maybe P(12) would be the population 12 years after the initial count. or P(0) would be the initial count of the population.

P₀ is the initial population at P(0)
r is the growth rate.<u><em> Don't forget to convert the percentage to its decimal form</em></u>

Now that everything is set out, lets use the equation to solve for our answer.

P(t) = P₀eʳᵗ

<u>Australia:</u>

$P(t)=(19169000)e^{(0.006)t}$

after 25 years

$P(25)=(19169000)e^{(0.006)(25)}=22271200.6$

<u>China:</u>

$P(t) = (1261832000)e^{(.009)t}$

after 25 years:

$P(25)=(1261832000)e^{(.009)(25)}=1580220878$

<u>Mexico:</u>

$P(t) = (100350000)e^{(0.018)t}$

after 25 years:

$P(25)=(100350000)e^{(0.018)(25)}=157380127.8$

<u>Zaire:</u>

$P(t) = (51965000)e^{(0.031)t}$

after 25 years:

$P(25)=(51965000)e^{(0.031)(25)}=112794819.9$

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stira [4]

Answer:

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Scrat [10]

Answer:

-4(y - 2) = 12

Standard form:

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Factorization:

−4(y + 1) = 0

Solutions:

y = −4

4

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Step-by-step explanation:

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