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Karolina [17]
2 years ago
15

a cylindrical tank has a volume of 100 gallons. a similar tank next to it has dimensions that are 2 times as large. what is the

volume of the larger tank?
Mathematics
1 answer:
Reil [10]2 years ago
8 0

The volume of the cylindrical tank is the amount of space in it

The volume of the larger tank is 800 gallons

<h3>How to determine the volume of the larger tank?</h3>

The volume of the small tank is given as:

v = 100

The volume of a cylinder is:

v = πr²h

For the bigger tank, we have:

V = πR²H

The dimensions are twice the smaller tank. This gives

V = π(2r)² * (2h)

Expand

V = 8πr²h

Substitute v = πr²h in V = 8πr²h

V = 8v

Substitute v = 100 in V = 8v

V = 8 * 100

V = 800

Hence, the volume of the larger tank is 800 gallons

Read more about volume at:

brainly.com/question/1972490

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3 hours

Step-by-step explanation:

Recall:

Distance = speed x time

we are given that speed = 18 km/h and distance = 54 km.

hence,

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time = 54/18 = 3 hours

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What is the solution to the system of equations?<br><br> {y=5x−10y=−3x+14
Dahasolnce [82]

Answer:

x = 3 and y = 5

Step-by-step explanation:

Given equations are :

y=5x−10 ..(1)

y=−3x+14 ...(2)

Subtract equation (2) from (1).

y-y = 5x−10-(−3x+14)

0 = 5x-10+3x-14

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Put the value of x in equation (1).

y=5(3)−10

= 15-10

y = 5

So, the values of x and y are 3 and 5 respectively.

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3 years ago
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3 years ago
Does the point ( 2, 1 ) satisfy the equation y = 2x?
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PLEASE HELP Given: △KLM LM=12, m∠K=60°, m∠M=45° Find: Perimeter of △KLM.
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We have to find the perimeter of the triangle KLM.

We have been given that the length of the side LM=12, m\angleK=60^\circ, and m\angle M= 45^\circ

Refer the attached image.

In a triangle sum of three angles should be 180^\circ.

So,

m\angle K+m\angle L+m\angle M=180^\circ

Plugging the values of angle K and angle M, we get:

60^\circ+m\angle L+45^\circ=180^\circ

So,

m\angle L=180^\circ-105^\circ=75^\circ

Now, that we have the measure of angle L, we will apply sine rule to find the length of the sides KL and KM.

Using the sine law for the triangle KLM, we get:

\frac{sin K}{LM}=\frac{sin L}{KM}=\frac{sin M}{KL}

Refer the image. Plugging the value of the sides of the triangle KLM and the angles of the triangle KLM, we get:

\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}=\frac{sin 45^\circ}{x}

Now using,

\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}

We get the value of 'y'

y=\frac{sin 75^\circ}{sin 60^\circ} \times 12=\frac{0.9659}{0.866} \times 12=13.38

So the length of the side KM is 13.38 units.

Now using,

\frac {sin 60^\circ}{12}=\frac{sin 45^\circ}{x}

We get the value of 'x'

x=\frac{sin 45^\circ}{sin 60^\circ} \times 12=\frac{0.707}{0.866} \times 12=9.79

So the length of the side KL is 9.79 units.

Now, to find the perimeter of the triangle KLM we need to sum up the length of the sides of the triangle KLM.

The perimeter of the triangle KLM = KL+ LM + KM = 9.79 + 12 + 13.38 = 35.17 units

6 0
3 years ago
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