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3 years ago

11

Mrs, O'Neil has 2 times as many markers as colored pencils. The total number of markers and colored pencils is 18. How many mark

ers does Mrs. O'Neil have?

1 answer:

Natali [406]3 years ago

5 0

36 I believe sorry if it’s wrong what I did was multiply 2x 18 have I nice day good luck!

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-6a-7<br><img src="https://tex.z-dn.net/?f=%20-%206a%20-%207%20%5Cleqslant%2017" id="TexFormula1" title=" - 6a - 7 \leqslant 17"

seropon [69]

$-6a-7\leq17\ \ \ \ |+7\\\\-6a\leq24\ \ \ \ |\text{change the signs}\\\\6a\geq-24\ \ \ |:6\\\\a\geq-4$

3 0

3 years ago

Solve the equation. Then check your solution. 5 /9 d = 9 /10 a. 31 / 90 c. 1/2 b. 1 31 /90 d. 50 /81

miskamm [114]

Answer:

d in (-oo:+oo)

(5/9)*d = 9/10 // - 9/10

(5/9)*d-(9/10) = 0

(5/9)*d-9/10 = 0

5/9*d-9/10 = 0 // + 9/10

5/9*d = 9/10 // : 5/9

d = 9/10/5/9

d = 81/50

d = 81/50

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

2/9 divided by 5/6<br>help pleaseee

igomit [66]

Hey there!

$\mathsf{\dfrac{2}{9}\div\dfrac{5}{6}}$

$\mathsf{= \dfrac{2\times6}{9\times5}}$

$\mathsf{2\times 6 = \bf 12}$

$\mathsf{9\times5 = \bf 45}$

$\boxed{\mathsf{=\bf \dfrac{12}{45}}}$

$\large\textsf{BOTH NUMBERS has the Greatest Common Factor (GCF) of 3}$

$\mathsf{= \dfrac{12\div3}{45\div3}}$

$\mathsf{12\div3=\bf 4}$

$\mathsf{45\div3=\bf 15}$

$\boxed{\mathsf{=\bf \dfrac{4}{15}}}$

$\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf \dfrac{4}{15}}}}\huge\checkmark$

$\large\textsf{Good luck on your assignment and enjoy your day!}\\\\\\~\frak{Amphitrite1040:)}}$

4 0

2 years ago

. Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals intersect at point P. Side QR = 17m, diagonal QS

trapecia [35]

Answer:

495 meter²

Step-by-step explanation:

In the given kite QRST,

PQ = PS = 15 meter

QR = 17 meter

We have to find the area of the kite.

Since kite is in the form of a rhombus.

and rhombus is = $\frac{1}{2}$ (Diagonal QS) × (Diagonal RT)

In Δ QRP,

17² = 15² + RP²

$\sqrt{17^{2}-15^{2}} = RP$

$RP=\sqrt{289-225}$

= √64 = 8 meters.

So RT = RP + PT = 8 + 25 = 33 meter.

Now area of kite = $\frac{1}{2}$ (30) (33) = 495 meter²

6 0

3 years ago

The percent of working students increased 8.1 to 40.5 what was the present prior to increase

Dmitrij [34]

Answer:

32.4

Step-by-step explanation:

prior + 8.1 = 40.5 . . . . . . seems to model the problem statement

prior = 32.4 . . . . . . . subtract 8.1 from both sides

Prior to the increase the percent was 32.4.

_____

<em>Comment on the problem statement</em>

When you're talking about a percentage increase in a percentage, it is almost never clear whether you're talking about the percentage of the underlying number, or the percentage of the percentage.

Here, we assume the 8.1 is a percentage of working students, not a percentage of the percentage of workings students. If you actually intend the latter, the percentage before the increase was about 37.465%.

6 0

2 years ago