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sammy [17]
3 years ago
9

gyms sandwich cost the same as the combined cost of his salad and milk. The sandwich cost three times as much as the milk. this

salad cost $.20 more than twice the cost of the milk. how much did Jim’s lunch cost
Mathematics
1 answer:
never [62]3 years ago
5 0

The answer would be no solution because the milks cansels out each other


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2. What is 5 percent of 700?
Stells [14]

Answer:

35

Step-by-step explanation:

700 / 100 = 7

7 = 1%

7 x 5 = 35

35 = 5%

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Last year Tamera made $42,786 how much did she make each month
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42,786  divided by 12 = 3,565.5

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1500 customers hold a VISA card; 500 hold an American Express card; and, 75 hold a VISA and an American Express. What is the pro
alex41 [277]

Answer:

There is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

P(VISA \:| \:AE) = 15\%\\

Step-by-step explanation:

Number of customers having a Visa card = 1,500

Number of customers having an American Express card = 500

Number of customers having Visa and American Express card = 75

Total number of customers = 1,500 + 500 = 2,000

We are asked to find the probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

This problem is related to conditional probability which is given by

P(A \:| \:B) = \frac{P(A \:and \:B)}{P(B)}

For the given problem it becomes

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}

The probability P(VISA and AE) is given by

P(VISA and AE) = 75/2000

P(VISA and AE) = 0.0375

The probability P(AE) is given by

P(AE) = 500/2000

P(AE) = 0.25

Finally,

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}\\\\P(VISA \:| \:AE) = \frac{0.0375}{0.25}\\\\P(VISA \:| \:AE) = 0.15\\\\P(VISA \:| \:AE) = 15\%\\

Therefore, there is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

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3 years ago
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X=7/2 which is equal to 3.5
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The following are the ages (years) of 5 people in a room:
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Is the answer 18/2 Nd very
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