A(R+T)=W
(A×R)+(A×T)=W
AR+AT=W
-AR from both sides
AT=W-AR
divide both sides by A
T=(W-AR)/A
Answer:
x = 15
Step-by-step explanation:
Given
See attachment
Required
Find x
The figure in the attachment is a quadrilateral and the angles in a quadrilateral add up to 360.
So, we have:
90 + 6x + 5+ 10x - 40 + 4x + 5 = 360
Collect like terms
6x + 10x + 4x = 360 - 90 - 5 + 40 - 5
20x = 300
Divide both sides by 20
x = 15
Hence, the value of x is 15
Answer:
265
Step-by-step explanation: Used a Calculator
<h3>E
xplanation:</h3>
Replace cos^2(θ) with 1-sin^2(θ), and cot(θ) with cos(θ)/sin(θ).
cos^2(θ)cot^2(θ) = cot^2(θ) - cos^2(θ)
(1 -sin^2(θ))cot^2(θ) = . . . . . replace cos^2 with 1-sin^2
cot^2(θ) -sin^2(θ)·cos^2(θ)/sin^2(θ) = . . . . . replace cot with cos/sin
cot^2(θ) -cos^2(θ) = cot^2(θ) -cos^2(θ) . . . as desired
I am not sure on this sorry ....... I think it's $5.00 .....
