If you would like to solve the system of equations, you can do this using the following steps:
2x - y = -2
x = 14 + 2y
__________
<span>2x - y = -2
</span>2 * (14 + 2y) - y = -2
28 + 4y - y = -2
28 + 3y = -2
3y = -2 - 28
3y = -30 /3
y = -30/3
y = -10
<span>x = 14 + 2y = 14 + 2 * (-10) = 14 - 20 = -6
</span>
(x, y) = (-6, -10)
The correct result would be <span>(-6, -10).</span>
Answer:
The solution of the system of equations is the point (-3,0)
Step-by-step explanation:
we have
-----> equation A
-----> equation B
Adds equation A and equation B
Find the value of y
The solution of the system of equations is the point (-3,0)
Answer:
The coordinates of C is (-8,1)
Step-by-step explanation:
Looking at the attached image, you'd see that, AB is 1 and BC is 1, that's because we are told that ratio of AB to AC is 1:2 meaning, AC is 2 and AB is 1. Therefore for that ratio to be satisfied BC has to be 1 so that AC would be 2.
Now let's assume the coordinates of C is 
.
To get it's coordinates, we use the section formula:
Where (m,n) is the (AB, BC)
Therefore we have
This gives:
and 
From there x = -8 and y = 1
Therefore the coordinates of C is (-8, 1).
Find the Mean, Median, Mode and Range of each series. Mean: 126 ÷ 9 = 14 1) 6 , 12 , 8 , 4 , 16 , 16 , 6 , 16 , 9 93 ÷ 9 2) 13 ,
Nadya [2.5K]
Answer:
129-14 is 115 than minus 6 than add 12
Step-by-step explanation:
Answer
∴ The true statement is Answer:
The true statement is BD ≅ CE ⇒ 3rd answer
Step-by-step explanation:
- There is a line contained points B , C , D , E
- All points are equal distance from each other
- That means the distance of BC equal the distance of CD and equal
the distance of DE
∴ BC = CD = DE
- That means the line id divided into 3 equal parts, each part is one
third the line
∴ BC = 1/3 BE
∴ CD = 1/3 BE
∴ DE = 1/3 BE
∵ BC = CD
∴ C is the mid-point of BD
∴ BC = 1/2 BD
∵ CD = DE
∴ D is the mid-point of DE
∴ CD = 1/2 CE
- Lets check the answers
* BD = one half BC is not true because BC = one half BD
* BC = one half BE is not true because BC = one third BE
* BD ≅ CE is true because
BD = BC + CD
CE = CD + DE
BC ≅ DE and CD is common
then BD ≅ CE
* BC ≅ BD is not true because BC is one half BD
∴ The true statement is BD ≅ CE
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