Question

How to solve this equation of the missing sides of the triangle

Answer 1

Step-by-step explanation:

Given is a 45°-45°-90 ° angled triangle.

By 45°-45°-90 ° angled triangle theorem:

side opposite to 45° angle is $\frac{1}{\sqrt 2}$ times of hypotenuse.

$\therefore \: 7 = \frac{1}{ \sqrt{2} } \times m \\ \\ \huge \red{ \boxed{\therefore \: m \: = 7 \sqrt{2} \: units}} \\ \\ n \: = \frac{1}{ \sqrt{2} } \times m \\ \\ \therefore \:n \: = \frac{1}{ \sqrt{2} } \times 7 \sqrt{2} \\ \huge \purple{ \boxed{\therefore \:n \: = 7 \: units}}$