Answer:
3
Step-by-step explanation:
lim(t→∞) [t ln(1 + 3/t) ]
If we evaluate the limit, we get:
∞ ln(1 + 3/∞)
∞ ln(1 + 0)
∞ 0
This is undetermined. To apply L'Hopital's rule, we need to rewrite this so the limit evaluates to ∞/∞ or 0/0.
lim(t→∞) [t ln(1 + 3/t) ]
lim(t→∞) [ln(1 + 3/t) / (1/t)]
This evaluates to 0/0. We can simplify a little with u substitution:
lim(u→0) [ln(1 + 3u) / u]
Applying L'Hopital's rule:
lim(u→0) [1/(1 + 3u) × 3 / 1]
lim(u→0) [3 / (1 + 3u)]
3 / (1 + 0)
3
Answer:
17/24, 7/12, 3/4, 2/3
Step-by-step explanation:
Answer: choice A) -4
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Step 1) Draw a vertical line through 1 on the x axis
Step 2) Mark the point where the vertical line and the blue curve intersect (or cross each other)
Step 3) Draw a horizontal line through the point marked in step 2. Note how this horizontal line goes through -4 on the y axis.
So the point (1,-4) is on the blue curve. This means if x = 1 is the input then y = -4 is the output. Recall that y = f(x). So f(x) = -4 is the output as well when the input is x = 1.
In short, this is why f(1) = -4
Integers are whole numbers that are either positive or negative. Operation of signs is important when dealing with integers.
In this case, -3 and -2 are integers that are being added.
if we add -3 by -2 we get -6 because when a negative number is added to a negative number the negative sign does not change
thus, (-3)-2 = -5
Answer:
The radius of the volleyball is 8.3 inches
Step-by-step explanation:
Given
Required
Determine the value of r
To do this, we simply substitute 288 for v and 3.14 for π in the given equation.
This gives
(Approximated)
Hence;
<em>The radius of the volleyball is 8.3 inches</em>
