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Alex Ar [27]
3 years ago
5

the pythagorean theorem states that a^2 + b^2 = c^2 If A and B represent the length of the legs of a right triangle and C repres

ents the length of the hypotenuse. Find the length of the hypotenuse Is the length of the legs are 9cm and 12cm.​
Mathematics
2 answers:
klio [65]3 years ago
7 0

Answer:

25 or 50 points is that if 25 or 20 im not

viktelen [127]3 years ago
5 0

Answer:

The hypotenuse equals 15cm

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Can anyone plzzz help me with this asap!!!
MaRussiya [10]
Answer: -9, -6, -3, 0, 3

EXPLANATION
Y = 3x - 3

So we need to plug in x.

X = -2 so

Y= 3(-2) -3

3 x -2 is -6

-6 - 3 is -9

So now we have y = -9

-9 is the first y value

Now x = -1

Y = 3(-1) -3

3 x -1 is -3

-3 - 3 = -6

The second y value is -6

Now x is 0

Y = 3(0) - 3

3 x 0 = 0

0 - 3 = -3

The third y value is -3

That’s all I’m going to do cause I think you get it by now and you can see the pattern, it’s going up be three. Hope this helps
4 0
3 years ago
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Solve the following system by the substitution method <br> 0.1x + 0.8y = - 5.1 , 0.4x- 0.9y = 8.3
Sav [38]
I hope you can read cursive! And I hope this helps! (:

6 0
3 years ago
HELP ME PLEASE! DUE TODAY
alukav5142 [94]

Answer:

Sorry it did not load

Step-by-step explanation:

4 0
3 years ago
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<img src="https://tex.z-dn.net/?f=y%2B%20%20%5Cfrac%7B13%7D%7B4%7D%20%20%3D%20%28x%5E2-%20%5Cfrac%7B1%7D%7B2%7D%20%29%5E2" id="T
zhenek [66]

Answer:    \bold{y=\dfrac{1\pm \sqrt{4x+13}}{2}}

<u>Step-by-step explanation:</u>

Inverse is when you swap the x's and y's and solve for y:

y+\dfrac{13}{4}=\bigg(x-\dfrac{1}{2}\bigg)^2\\\\\\x+\dfrac{13}{4}=\bigg(y-\dfrac{1}{2}\bigg)^2\rightarrow \text{(swapped the x's and y's)}\\\\\\\sqrt{x+\dfrac{13}{4}}=\sqrt{\bigg(y-\dfrac{1}{2}\bigg)^2}\rightarrow \text{(took square root of both sides)}\\\\\\\sqrt{\dfrac{4x+13}{4}}=\pm \bigg(y-\dfrac{1}{2}\bigg)}\rightarrow \text{(created common denominator in radical)}\\\\\\ \dfrac{\sqrt{4x+13}}{2}=\pm \bigg(y-\dfrac{1}{2}\bigg)}\rightarrow \text{(simplified radical)}

\pm \dfrac{\sqrt{4x+13}}{2}=y-\dfrac{1}{2}}\rightarrow \text{(divided both sides by}\ \pm )\\\\\\\dfrac{1}{2}\pm \dfrac{\sqrt{4x+13}}{2}=y\quad \rightarrow \text{(added}\ \dfrac{1}{2}\ \text{to both sides)}\\\\\\\dfrac{1\pm \sqrt{4x+13}}{2}=y\quad \rightarrow \text{(combined numerators)}

4 0
3 years ago
The equation $y = -6t^2 - 10t + 56$ describes the height (in feet) of a ball thrown downward at 10 feet per second from a height
blondinia [14]

Answer:

2.33 Seconds

Step-by-step explanation:

The equation y = -6t^2 - 10t + 56 expresses the height of a ball at a given time, t, on the planet Mars.  We are also given that the ball is thrown with a velocity of 10 feet per second with the initial height of 56 feet.

To find the amount of time to reach the ground, we can say that the time being found will be when the ball is on the ground, or when y = 0.  So we simply set our equation to 0 and solve for t.

y = -6t^2 - 10t + 56

0 = -6t^2 - 10t + 56

0 = -1 (6t^2 + 10t + -56)

0 = -1 (3t - 7) (2t + 8)

(3t - 7) = 0  OR (2t + 8) = 0

3t = 7         OR  2t = -8

t = 7/3        OR    t = -4

Since time will not be negative, we will want to choose the positive solution for this quadratic equation.

Hence, the amount of time for the ball to hit the ground will be 7/3 seconds or 2.33 seconds.

Cheers.

5 0
3 years ago
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