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Vedmedyk [2.9K]
3 years ago
5

The playground at a park is shaped like a trapezoid the dimensions what is the area of the playground in square feet

Mathematics
1 answer:
Maru [420]3 years ago
5 0

Answer:

Area = 1560ft^2

Step-by-step explanation:

Given

See attachment for playground

Required

Determine the area

The playground is a trapezoid. So;

Area = \frac{1}{2}(Sum\ parallel\ sides) * Height

From the attachment, the parallel sides are: 68ft and 36ft

The height is: 30ft

So, the area is:

Area = \frac{1}{2}(68ft + 36ft) * 30ft

Area = \frac{1}{2}(104ft) * 30ft

Area = 52ft * 30ft

Area = 1560ft^2

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The diameter of Circle Q terminates on the circumference of the circle at (3,0) and (3,-7) . Write the equation of the circle in
Deffense [45]

Step-by-step explanation:

The center of a circle with 2 end points of a di diameter is the midpoint of the two endpoints.

The formula needed to find the minpoints is

(x,y) = (x2 + x1)/2, (y2 + y1)/2

x2 = 3

x1 = 3

y2 = 0

y1 = -7

midpoint = (3 + 3)/2, (0 - 7)/2

midp[oint = 3,-3.5

The midpoint is the center of the circle. Observe that the signs get changed when entering the values for (x,y)

So far what you have is (x - 3)^2 + (y + 3.5)^2 = r^2

To determine r^2 you need only take the distance from the center to oneof the endpoints.

r^2 = (3 - 3)^2 + (3.5 - 0)^2

r^2 = 3.5^2

r^2 = 12.25

Answer: (x - 3)^2 + (y + 3.5)^2 = 12.25

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3 years ago
One solution to the problem below is 4.<br> What is the other solution?<br> y² - 16 = 0
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Answer:

The 2 answers are 4 and -4

Step-by-step explanation:

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3 years ago
Can someone help me out? Pls it’s urgent!!! ASAP! (Geometry)<br> “Complete the proof”
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I really need help with this ! Thanks !
slamgirl [31]
SohCahToa

Sin=oposite side/hyptoonuse
Cos=adjacent side/hypotonuse
Tan=oposite side/hypotonuse

oposite side is the side oposite the angle
adjacent side is the side touching the angle that isn't the hypotonuse
hypotonuse is longest side





1.
first solve for hypotonuse using a²+b²=c²
hypotonuse=13
sinA=12/13
cosA=5/13
tanA=12/5
sinB=5/13
cosB=12/13
toa=5/12


2. the missing side is 8
sinD=15/17
cosD=5/17
tanD=15/5=3
sinE=5/17
cosE=15/17
tanE=5/15=1/3


3. missing side is 25
you should be able to do this
sinG=7/25
do the rest


4.
missing side is 6
sinJ=6/10=3/5
do the rest
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3 years ago
What is the area of ABDC? Assume ABDC lies in the center of the larger rectangle.
MrRa [10]
The area of rectangle ABCD should be 24. Since the length is 6 and the height is 4.
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