(Snowflakelove please help) Let f(x) represent a function. Which descriptions match the given transformations?

Mathematics

2 answers:

wlad13 [49]3 years ago

7 0

I am pretty sure it is d, f, and a

harina [27]3 years ago

5 0

It would be D and A

I hope I've helped!

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A karat equals 1/24 part of gold in an alloy [ eg 9 karat gold is 9/24 gold]. How many grams of 9 karat gold must be mixed with

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This is a mixture problem.

Let the 9 karat gold to be mixed be x. The 18 karat would weight (200 - x). Since the total = 200g.

mass1 * karat1 + mass2*karat = total mass * total carat

Let mass1 be x g. mass 2 would be = (200 -x)
karat 1 = 9 karat 2 = 18

Total mass = 200g.
Total karat = 14.

9*x + 18*(200 -x) = 14*200

9x + 18*200 - 18*x = 14*200

18*200 + 9x - 18x = 14*200

3600 - 9x = 2800

3600 - 2800 = 9x

800 = 9x

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x = 800/9

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Tim must read 2 books from a list of 7 recommended books for his summer reading program. In how many different ways can Tim choo

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There are 21 ways Tim choose 2 books from the 7 recommended book

Solution:

Given that Tim must read 2 books from a list of 7 recommended books for his summer reading program

To find: different ways can Tim choose 2 books from the 7 recommended books

This is a combination problem

A combination is a selection of all or part of a set of objects, without regard to the order in which objects are selected

The formula for combinations is:

$n C_{r}=\frac{n !}{r !(n-r) !}$

where n represents the number of items, and r represents the number of items being chosen at a time

Here we have to choose 2 books from 7 books

Therefore, n = 7 and r = 2

Substituting values in above formula, we get

$\begin{aligned}&7 C_{2}=\frac{7 !}{2 !(7-2) !}\\\\&7 C_{2}=\frac{7 !}{2 ! \times 5 !}\end{aligned}$

For a number n, the factorial of n can be written as,

$n !=n \times(n-1) \times(n-2) \dots \dots \times 2 \times 1$

Therefore, we get

$7 C_{2}=\frac{7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}{2 \times 1 \times 5 \times 4 \times 3 \times 2 \times 1}\\\\7C_2 = 7 \times 3 = 21$