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mina [271]
2 years ago
5

<><><><>Simple true and false math<><><><>

Mathematics
1 answer:
skad [1K]2 years ago
7 0

Answer:

true

Step-by-step explanation:

just my opinion but for me it's true

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"Part A: Solve −np − 70 &lt; 40 for n. Show your work."
damaskus [11]
-np - 70 < 40 -np < 40 + 70 -np < 110 -np/-p < 110/-p n < 110/-p 4w - 7k = 28 4w-4w-7k = 28 - 4w -7k = 28 - 4w -7k/-7 = 28-4w /-7 k = 28-4w/-7
4 0
3 years ago
Mike wants to make meatloaf. His recipe uses a total of 3 pounds of meat. If he uses a 3 to 1 ratio of beef to pork, how much po
nadezda [96]
Beef to pork.....ratio 3:1....added = 4.....this is basically saying that 3/4 of the total meat is beef and 1/4 of the total meat is pork...and the total meat is 3 lbs.

3/4(3) = 9/4 = 2 1/4 lbs of beef
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8 0
3 years ago
Find the value of x and the value of y.
stepladder [879]

Answer:

the 3rst one

Step-by-step explanation:

4 0
3 years ago
Multiply. Write your answer as a fraction in simplest form.<br><br> −1(4/5)=
Cerrena [4.2K]

Answer: -4/5

Step-by-step explanation:

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6 0
3 years ago
Anita invested $6000, some at 5% and the rest at 6%. If the yearly income is $337.50, what is the amount invested at each rate?
Pepsi [2]

Let the amount invested with 5% interest be x

Therefore, the amount invested with 6% interest will be (6000-x)

It is given that the total interest earned yearly is $337.5. Thus, the equation of interest will be:

\frac{5}{100}x+\frac{6}{100}(6000-x)=337.5

Multiplying both sides by 100 we get:

5x+6(6000-x)=33750

5x+36000-6x=33750

Subtracting both sides by 36000 we get:

-x=-2250

\therefore x=2250

Thus, the amount invested at 5% is $2250

Therefore, the amount invested at 6% will be $(6000-2250)=$3750

6 0
3 years ago
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