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oksano4ka [1.4K]
2 years ago
9

Help pls 30 points dont know how and what this is

Mathematics
1 answer:
joja [24]2 years ago
8 0

Answer:

I think it is either D or E, probably D, but if it is E it's because the money should be on top.

Answer: D

Step-by-step explanation:

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I think it’s 6,9,16 for the answer
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What is the probability of having an odd number in a single toss of a fair die?
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If I'm not mistaken, the correct answer would be the probability is 3/6 or 1/2. Hope this helps :D
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3 years ago
A breeder reactor converts uranium-238 into an isotope of plutonium-239 at a rate proportional to the amount of uranium-238 pres
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Let U(t) denote the amount of uranium-238 in the reactor at time t. As conversion to plutonium-239 occurs, the amount of uranium will decrease, so the conversion rate is negative. Because the rate is proportional to the current amount of uranium, we have

\dfrac{\mathrm dU}{\mathrm dt}=-kU

where k>0 is constant. Separating variables and integrating both sides gives

\dfrac{\mathrm dU}U=-k\,\mathrm dt\implies\ln|U|=-kt+C\implies U=Ce^{-kt}

Suppose we start some amount u. This means that at time t=0 we have U(0)=u, so that

u=Ce^{-0k}\implies C=u\implies U=ue^{-kt}

We're given that after 10 years, 99.97% of the original amount of uranium remains. This means (if t is taken to be in years) for some starting amount u,

0.9997u=ue^{-10k}\implies k=-\dfrac{\ln(0.9997)}{10}

The half-life is the time t_{1/2} it takes for the starting amount u to decay to half, 0.5u:

0.5u=ue^{-kt_{1/2}}\implies t_{1/2}=-\dfrac{\ln(0.5)}k=\dfrac{10\ln2}{\ln(0.9997)}

or about 23,101 years. Notice that it doesn't matter what the actual starting amount is, the half-life is independent of that.

7 0
3 years ago
11.717, 11.771, 11.117, 11.171 greatest to least
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Knowing the value of each digit, we can arrange them from greatest to least like so:

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Answer:

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Step-by-step explanation:

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