Probably the anti virus, so you don't get a virus from downloading the anti spyware program.
Answer:
The algorithm to find A is even or odd.
- input A.
- Check the remainder on diving by 2 by A%2.
- If remainder is 1 then A is odd Print(Odd).
- If remainder is 0 print(Even).
Explanation:
To check if the number is even or odd we use modulo operator(%).Which gives the remainder on dividing.So if we do this A%2 it will give the remainder that will come out on dividing the value of A by 2.
So if the remainder comes out is 1 then the number is odd and if the remainder is 0 then the number is odd.
Answer:
// Program is written in C++ Programming Language
// Comments are used for explanatory purpose
// Program starts here
#include<iostream>
using namespace std;
int main()
{
// Declare integer variable n which serves as the quotient.
int n;
// Prompt to enter any number
cout<<"Enter any integer number: ";
cin>>n;
// Check for divisors using the iteration below
for(int I = 1; I<= n; I++)
{
// Check if current digit is a valid divisor
if(n%I == 0)
{
// Print all divisors
cout<<I<<" ";
}
}
return 0;
}
