Answer:
b,d,f are the answers......
Yes; his answer is correct.
John can do this by multiple ways, but most likely he just remembered this one. Here are some ways.
1. He used his fingers; he put 1 finger, then another finger, and got 2 fingers up. The answer is 2.
2. He remembered it; usually Kindergarteners learn this and this is very easy to remember.
3. He used the things around him; I have 1 crayon then add another, how many do I have? 2.
Answer:
See below.
Step-by-step explanation:
So, we have:
Recall that secant is simply the reciprocal of cosine. So we can:
Now, recall the unit circle. Since cosine is negative, it must be in Quadrants II and/or III. The numerator is the square root of 3. The denominator is 2. The whole thing is negative. Therefore, this means that 150 or 5π/6 is a candidate. Therefore, due to reference angles, 180+30=210 or 7π/6 is also a candidate.
Therefore, the possible values for theta is
5π/6 +2nπ
and
7π/6 + 2nπ
-2(1/4x+2) >= 5
-0.5x-4 >= 5
-0.5x >= 9
x >= -18
The y intercepts are when x=0 (the line crosses the y axis) and the x intercepts are when y=0 (the line crosses the x axis). Plugging x=0 in, we get 5*0=2y+4. Subtracting 4 from both sides, we get -4=2y and by dividing both sides by 2 we get y=-2, for one intercept to be (0, -2). For the other intercept, we make y=0 to get 5x=2*0+4=4. Dividing both sides by 4, we get x=4/5, making our other intercept (4/5, 0)
