Answer:
Option B, Spencer did not factor the polynomial completely; 16x^2−1 can be factored over the integers.
Step-by-step explanation:
<u>Step 1: Factor</u>
256x^4y^2−y^2
y^2(256x^4 - 1)
y^2(16x^2 - 1)(16x^2 + 1)
<em>y^2(</em><em>4x + 1)(4x - 1</em><em>)(16x^2 + 1)</em>
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Answer: Option B, Spencer did not factor the polynomial completely; 16x^2−1 can be factored over the integers.
no bc once multiplied it equald 0.18
Answer:
160 and 70
Step-by-step explanation:
will be your answer