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3 years ago

Spencer is asked to factor the polynomial 256x^4y^2−y^2 completely over the integers. His work is shown below.

Mathematics

2 answers:

mr Goodwill [35]3 years ago

7 0

Answer:

Option B, Spencer did not factor the polynomial completely; 16x^2−1 can be factored over the integers.

Step-by-step explanation:

Step 1: Factor

256x^4y^2−y^2

y^2(256x^4 - 1)

y^2(16x^2 - 1)(16x^2 + 1)

y^2(4x + 1)(4x - 1)(16x^2 + 1)

Answer: Option B, Spencer did not factor the polynomial completely; 16x^2−1 can be factored over the integers.

Olegator [25]3 years ago

5 0

Answer:

answer B

Step-by-step explanation:

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2 years ago

Is -2 a solution to 4x^(3)-x^(2)+16x-4

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Answer:

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Step-by-step explanation:

In order for $x=-2$ to be a solution, the result after substituting must be 0:

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Answer:

Step-by-step explanation:

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