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zzz [600]
3 years ago
11

Consider the following set of 19 data values:

Mathematics
1 answer:
storchak [24]3 years ago
6 0

Answer:

mean = 5.4

median  = 5

mode = is the number that appears the most answer = 5

Step-by-step explanation:

mean

5+6+6+9+10+4+2+5+7+6+7+3+5+5+5+4+9+2+10  =       .........   / 19 = 5.4

median

2 2  3 4 4 5 5 5 5 5 6 6 6 7 7 9 9 10 10 then find the middle between these = 5

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How many hundredths are in 539.26? Is the answer 6? Or is 6 just in the hundredth’s spot
Novosadov [1.4K]

Answer:

its 600 because its in the hundredths place so it would be 6 hundredths

Step-by-step explanation:

3 0
4 years ago
?!?!?!CAN ANYONE PLEASE HELP<br> ME??!!?!?
Ann [662]

\begin{gathered}\\ \sf\longmapsto x^{2}-6x\end{gathered}

\large\red{\sf{Name\:according\:to\:degree}}

  • It is quadratic polynomial.
  • A quadratic polynomial has 2 as its degree.

\large\green{\sf{Name\:according\:to\:number\:of\:terms}}

  • It is monomial.
  • A monomial consists of one term.

\begin{gathered}\\ \sf\longmapsto x+5\end{gathered}

\large\purple{\sf{Name\:according\:to\:degree}}

  • It is constant or zero polynomial.
  • When a term doesn't have any degree it is termed as zero or constant polynomial.

\large\pink{\sf{Name\:according\:to\:number\:of\:terms}}

  • It is also a monomial.
  • Because it consists of only one term.

\begin{gathered}\\ \sf\longmapsto -9\end{gathered}

\large\blue{\sf{Name\:according\:to\:degree}}

  • It is constant or zero polynomial.
  • Because it doesn't have any power.

\large\orange{\sf{Name\:according\:to\:number\:of\:terms}}

  • It is again a monomial.
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7 0
3 years ago
An experiment consists of choosing objects without regards to order. Determine the size of the sample space when you choose the
sdas [7]

Answer:

a

    n=  75, 582

b

  n=    2300

c

  n =   253

Step-by-step explanation:

     Generally the size of the sample sample space is  mathematically represented as

           n  =   \left N } \atop {}} \right.  C_r

Where   N is the total number of objects available and  r is the  number of objects to be selected

    So  for  a,  where N = 19  and r = 8  

         n  =   \left 19 } \atop {}} \right.  C_8 =  \frac{19 !}{(19 - 8 )! 8!}

                           =     \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}

                           n=  75, 582

    For  b  Where  N  = 25 and  r  =  3

           n  =   \left 25 } \atop {}} \right.  C_3 =  \frac{25 !}{(19 - 3 )! 3!}

                             =     \frac{25 *24 *23 *22 !  }{22 ! \ 3!}

                             n=    2300

   For  c  Where  N  = 23 and  r  =  2

            n  =   \left 23 } \atop {}} \right.  C_2 =  \frac{23 !}{(23 - 2 )! 2!}

                              =     \frac{23 *22 *21!  }{21 ! \ 3!}

                              n =   253

4 0
4 years ago
peaches are 1.79 a pound at the grocery store.if kim bought 3.5 pounds of peaches how much did she spend?
Westkost [7]
She spent 6.265 pounds, if you round it to the nearest hundredth, it would be 6.27 pounds
4 0
1 year ago
Find the sum (6y – 2) + (5y + 5)
slavikrds [6]

Answer:

11 y + 3

Step-by-step explanation:

(6y-2) + (5y+5)

Add 6y and 5y

11y - 2 + 5

Add -2 and 5

11 y + 3

7 0
3 years ago
Read 2 more answers
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