Answer:
Numer 1
A) (-5, -4), (-4, -3), (-3, -2), (-2, -1) Is a function
Number 2
C) (-5, -1), (-2, -1), (1, -1), (4, -1) is a function
so 40 * 80 = 3,200
4 * 8 = 32
Then add the two 0's to the end
so 3,200
The -3 would be where your line crosses the y-axis, so you would plot your point at -3. your slope will always be counted as rise/run, basically meaning you would count along the y-axis a certain amount of times, in this case -1, and along the x-axis a certain amount of times, here would be three. your next plot point would be (3,-4) and so on. hope this helped!
The given inequality holds for the open interval (2.97,3.03)
It is given that
f(x)=6x+7
cL=25
c=3
ε=0.18
We have,
|f(x)−L| = |6x+7−25|
= |6x−18|
= |6(x−3)|
= 6|x−3|
Now,
6|x−3| <0.18 then |x−3|<0.03 ----->−0.03<x-3<0.03---->2.97<x<3.03
the given inequality holds for the open interval (2.97,3.03)
For more information on inequality click on the link below:
brainly.com/question/11613554
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Although part of your question is missing, you might be referring to this full question: For the given function f(x) and values of L,c, and ϵ0, find the largest open interval about c on which the inequality |f(x)−L|<ϵ holds. Then determine the largest value for δ>0 such that 0<|x−c|<δ→|f(x)−|<ϵ.
f(x)=6x+7,L=25,c=3,ϵ=0.18
.
Answer:
3
Step-by-step explanation:
The GCF is the largest number that is a factor of the numbers listed. In this case, since one of the numbers is a constant the GCF will not have a variable. However, all of the numbers can be divided by 3. This is because 3 is the GCF.
