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lorasvet [3.4K]
2 years ago
10

Hey can yall please help me its 4'1 minuse 1'10​

Mathematics
2 answers:
neonofarm [45]2 years ago
7 0
4’1= 4 feet and 1 inch
12 inches= 1 ft.
12(4)= 48 ; 48+ 1inch = 49 inches
1’10= 1 foot and 10 inches
1(12)= 12 + 10 = 22
49-22= 27 inches !
hoa [83]2 years ago
3 0
<h3>Answer:  2' 3"</h3>

In other words, it's 2 feet, 3 inches

=================================================

Work Shown:

Convert the 4'1" to purely inches only

4'1" = 4 ft, 1 inch

4'1" = 4 ft + 1 inch

4'1" = 48 inches + 1 inch

4'1" = 49 inches

Note how 4 ft = 4*12 = 48 inches

-------------------

Through similar steps, you should find that 1'10", aka 1 ft 10 inches, is equivalent to 22 inches

Subtracting the two quantities gets us

(4' 1") - (1' 10") = (49 inches) - (22 inches) = 27 inches

Now convert that to the format "feet,inches".

27 in = 24 in + 3 in

27 in = (24/12 ft) + 3 in

27 in = 2 ft + 3 in

27 in = 2 ft, 3 in

27 in = 2' 3"

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Answer:

a. A = C_{0}(1-x)^t\\x: percentage\ of \ caffeine\ metabolized\\

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Step-by-step explanation:

First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

A= C_{0}(1-x)^t\\t: time \ in \ hours\\x: percentage \ of \ caffeine\ metabolized\\

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

\frac{dA}{dt} =C_{0}(1-x)^t \ln (1-x)\\\frac{dA}{dt} =100*0.88\ln(0.88)\\\frac{dA}{dt} =-11.25 \frac{mg}{h}

The rate is negative as it represents the amount of caffeine leaving the body at certain time.

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