Answer: it's A
Step-by-step explanation: Its A I bet nonono C
U = ( -8 , -8)
v = (-1 , 2 )
<span>the magnitude of vector projection of u onto v =
</span><span>dot product of u and v over the magnitude of v = (u . v )/ ll v ll
</span>
<span>ll v ll = √(-1² + 2²) = √5
</span>
u . v = ( -8 , -8) . ( -1 , 2) = -8*-1+2*-8 = -8
∴ <span>(u . v )/ ll v ll = -8/√5</span>
∴ the vector projection of u onto v = [(u . v )/ ll v ll] * [<span>v/ ll v ll]
</span>
<span> = [-8/√5] * (-1,2)/√5 = ( 8/5 , -16/5 )
</span>
The other orthogonal component = u - ( 8/5 , -16/5 )
= (-8 , -8 ) - <span> ( 8/5 , -16/5 ) = (-48/5 , -24/5 )
</span>
So, u <span>as a sum of two orthogonal vectors will be
</span>
u = ( 8/5 , -16/5 ) + <span>(-48/5 , -24/5 )</span>
The answer would be D. Infinite
Isolate the p. Note the equal sign. What you do to one side, you do to the other. Multiply 7/6 to both sides
(-2)(7/6) = (6/7)(7/6)p
p = (-2)(7/6)
Multiply -2 and 7, then divide by 6
p = (-2 x 7)/6
p = -14/6
Divide
p = ~-2.33 (rounded)
-2.33 is your answer
hope this helps
Answer:
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