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Rufina [12.5K]
3 years ago
11

Please answer number 44 please

Mathematics
1 answer:
sergejj [24]3 years ago
6 0

8.85-1.71=7.14

7.14g/cm³

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The fractions and decimals in order from least to greatest 7/48 0.5 0.75 9/16
katen-ka-za [31]

Answer:

7/48,0.5,9/16,0.75

Step-by-step explanation:

Hope this helps

6 0
3 years ago
Can you explain how to solve this?
alexandr1967 [171]
See attachment for steps

Answer: 1.77

Hope this helps!

8 0
3 years ago
What is the value of x in the triangle?
yulyashka [42]
<h3>Answer: C) x = 13</h3>

====================================================

Work Shown:

We have a right triangle with legs a = 5 and b = 12. The hypotenuse is c = x which is unknown for now.

Use the pythagorean theorem to find x.

a^2 + b^2 = c^2

5^2 + 12^2 = x^2

25 + 144 = x^2

169 = x^2

x^2 = 169

x = sqrt(169)  .... apply the square root to both sides

x = 13

4 0
3 years ago
Aaron bought a new television that has a 92 in. 76 in. screen. It has a feature that splits the screen to allow him to watch 4 c
castortr0y [4]

Answer:

The scale factor is equal to 1/2

The dimensions of each channel when splits the screen is 46 in x 38 in

Step-by-step explanation:

we know that

The dimensions of the new television is 92 in x 76 in

Remember that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

A1 -----> the area of the new television

A2 ----> the area of each channel when splits the screen

z-----> the scale factor

z^{2} =\frac{A2}{A1}

we have that

The area of the new television is 4 times the area of each channel

A1=4A2

(A2/A1)=1/4

z^{2} =\frac{1}{4}

z=\frac{1}{2} -----> the scale factor

so

When splits the screen, the dimension of each channel is equal to

92/2 in x 76/2 in

so

46 in x 38 in

Remember, if two figures are similar then the scale factor is equal to the ratio of their corresponding sides

<em>Verify the value of the scale factor</em>

92/46=1/2

or

76/38=1/2

8 0
4 years ago
(Find the Probability Question)<br><br> Choose 2 girls from a class of 12 boys and 8 girls.
Ulleksa [173]

Step-by-step explanation:

what should be the question ?

how many different pairs of 2 girls can you pick out of 8 ?

what is the probability that a specific girl is in the picked pair ?

or is it : if you pick randomly 2 students from the class, what is the probability to have picked 2 girls ?

and there are more options.

but I assume the problem is the picking randomly 2 students.

so, it is 20 students (12 + 8). if we pick 1 student, we have a chance of 12/20 = 3/5 to pick a boy, and a chance of 8/20 = 2/5 to pick a girl.

in our experiment we pick 2 students in a row without returning the first pick into the main pool.

the probabilty for the first pick to be a girl is, as mentioned, 2/5 or 0.4.

for the second pick we have only 7 out of 19 choices to pick a girl. so, the probability to pick a girl now is 7/19.

the combination of both (non-overlapping) probabilities is done via multiplication, and the probabilty to pick 2 girls is :

2/5 × 7/19 = 2×7 / 5×19 = 14/95 = 0.147368421...

7 0
2 years ago
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