Answer:
566 ft
Step-by-step explanation:
Given the polynomial equation
-16t² + 300t + 30 = 0
We're asked to find how high the rocket would rise in a 2 second fuse rise. This is a simple instruction that can be obtained by setting the unknown, t, in the equation to 2. Doing this, we have
-16 * 2² + 300 * 2 + 30
-16 * 4 + 600 + 30
-64 + 630 = 566 ft
Then, we can therefore conclude that the rocket will rise high up to a distance of 566 ft
Answer: 0.28
Step-by-step explanation:
Answer:
(x + 5, y + 1)
Step-by-step explanation:
As we can see, what we have is a translation
let us pick a point
G( -5,-2)
To;
G’(0,-1)
so the shift on the x-axis is;
(0-(-5)) = 5
shift on the y-axis is;
(-1-(-2) = 1
we have a rightward shift of 5 units on the x-axis and 1 unit on the y-axis
So we have the rule as;
(x + 5, y + 1)
Answer:
1/4 -or- 4
Step-by-step explanation:
take the x-axis value 16 and divide by the other x-axis value, 4.
Answer:
Step-by-step explanation:
