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LekaFEV [45]
3 years ago
9

Given (9,4) and (x,−11), find all x such that the distance between these two points is 17. Separate multiple answers with a comm

a.
Mathematics
1 answer:
MrRa [10]3 years ago
7 0

Answer:

The points are (1, -11) and (17, -11).

Step-by-step explanation:

The distance between points (x1, y1) and (x2, y2) is

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

We have values for x1, y1, and y2. We leave x for x2, and we solve for x.

17 = \sqrt{(x - 9)^2 + (-11 - 4)^2}

Square both sides.

289 = (x - 9)^2 + (-11 - 4)^2

289 = x^2 - 18x + 81 + 225

x^2 - 18x + 17 = 0

(x - 1)(x - 17) = 0 [/tex}[tex] x - 1 = 0   or   x - 17 = 0

x = 1 or x = 17

The points are (1, -11) and (17, -11).

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Richard is given one of four pieces of equal-sized fabric. After using some of his fabric for a project, he has 5/6 of a square
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Answer:

Richard used 2\frac{1}{12}\ yd ^2 of fabric for his project.

Step-by-step explanation:

Given:

Total amount of fabric = 11\frac23\ yd^2

Now To convert a mixed fraction to an improper fraction, Multiply the whole number part by the fraction's denominator,  Add that to the numerator,Then write the result on top of the denominator.

11\frac23\ yd^2 can be Rewritten as \frac{35}{3}\ yd^2

Number of pieces fabric was cut = 4

Richard is given one of four pieces of equal-sized fabric.

Amount of fabric Richard was given = \frac14 \times \frac{35}{3}=\frac{35}{12}\ yd^2

Amount of fabric left with Richard = \frac56 \ yd^2

We need to find the amount of fabric Richards used for his project.

Solution:

Now we can say that;

amount of fabric Richards used for his project is equal to Amount of fabric Richard was given minus Amount of fabric left with Richard.

framing in equation form we get;

amount of fabric Richards used for his project = \frac{35}{12}-\frac56

Now we will make the denominator common using LCM we get;

amount of fabric Richards used for his project = \frac{35}{12}-\frac{5\times2}{6\times2} = \frac{35}{12}-\frac{10}{12}

Now Denominator is same so we will solve the numerator.

amount of fabric Richards used for his project  = \frac{35-10}{12}= \frac{25}{12}\ yds^2

\frac{25}{12}\ yds^2 can be rewritten as 2\frac{1}{12}\ yd ^2

Hence Richard used 2\frac{1}{12}\ yd ^2 of fabric for his project.

7 0
3 years ago
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