(9b -7) +(7-3b) - (-3-3b) +(6+3b) = 9b -7 + 7-3b +3 + 3b + 6+3b = 12b + 9
We have 4 numbers (9b -7) and (7-3b), and - (-3-3b), and (6+3b).
To find the average, we need the sum of these numbers 12b + 9, divide by 4.
(12b + 9)/4 = 3b +9/4
Answer is A.
Answer:
100units^2
Step-by-step explanation:
Using pythagoras theorem, it states that 36+64= area of the unknown
Answer:
A
Step-by-step explanation:
z = -3 - 5i
z (i) = i (-3 - 5 i)
z (i) = -3i - 5i^2
z (i) = -3i - 5 (-1)
z (i) = -3i + 5
z (i) = 5 - 3i
Therefore, letter A is the correct answer.
Answer:
Greater than or >
Step-by-step explanation:
.03 + .60 = .63
.30 + .06 = .36
.63 ___ .36
.63 > .36
If sin < 0 and sec > 0, theta must be located in quadrant IV where tan < 0
Use x for theta
So to compute for this:Sec x = √10/3
cos x = 3 / √10
sin x = -√(1-cos^2x)
= -√ (1-(9/10))
= -√ (1/10)
= -1/√10
tan x = sin x/cos x
=-1/3 is the answer for this problem.