Answer:
D. (1/4, -2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = -8x
4x - y = 3
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 4x - (-8x) = 3
- Simplify: 4x + 8x = 3
- Combine like terms: 12x = 3
- Isolate <em>x</em>: x = 3/12
- Simplify: x = 1/4
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define equation: y = -8x
- Substitute in <em>x</em>: y = -8(1/4)
- Multiply: y = -2
Answer:
a = √11 and b = 6
Step-by-step explanation:
Refer to attached picture for reference
for an right triangle with angle θ
we are given
cos θ = 5/6 = length of adjacent side / length of hypotenuse
hence
adjacent length = 5 units
hypotenuse length = 6 units
the missing side is the "opposite" length which we can find with the Pythagorean equation. in our case:
hypotenuse ² = adjacent ² + opposite² (rearrange)
opposite ² = hypotenuse ² - adjacent ²
opposite ² = 6² - 5²
opposite = √ (6²-5²) = √11
sin θ = opposite length / hypotenuse (substitute values above)
sin θ = √11 / 6
hence a = √11 and b = 6
Answer:
x = 45
y = 45
z = 11.1
Step-by-step explanation:
Remark
The triangle is a right triangle. That means that it has 1 right angle.
It is also isosceles which means that the two legs that are not the hypotenuse are equal.
Result: z and 11.1 are equal z = 11.1
More remark
If the triangle is isosceles, that means that the angles that are not right angles must also be equal.
90 + x + y = 180
but x = y
90 + 2x = 180 Subtract 90
2x = 180 - 90 Divide by 2
2x/2 = 90/2
x = 45
Now, there are many types of solids. Hypothesis can be stated as there is a significant discrepancy between solid one from the other sold. Moreover, if the results seems to support the hypothesis then it is somehow reliable and accurate.Thank you for your question. Please don't hesitate to ask in Brainly your queries.