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Svetradugi [14.3K]
3 years ago
9

Select True or False for each statement.

Mathematics
1 answer:
son4ous [18]3 years ago
4 0

Answer:

i made this so u can mark the other answer brainiest

Step-by-step explanation:

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What is the formula of circle​
gogolik [260]

Answer:

Area = pi r squared

Step-by-step explanation:

If you need to, sometimes your teacher will ask you to leave you answers in terms of pi, or keep pi as 3.

3 0
2 years ago
Read 2 more answers
Determine whether the given measures can be the lengths of the sides of a triangle write yes or no
ohaa [14]

NO.,the given measures can not be the lengths of the sides of a triangle

Step-by-step explanation

The sum of the lengths of any two sides of a triangle must be greater than the length of the third side.

so, Find the range for the measure of the third side of a triangle given the measures of two sides.

here given measures are 2,2,6

2+2 = 4 which is less than the third side 6

        = 4 < 6    

This not at all a triangle.

Hence, the given measures can not be the lengths of the sides of a triangle

3 0
4 years ago
I wanted to knwo what two to the third power was please help
nikitadnepr [17]
Eight is the answer.
8 0
4 years ago
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Find the equation of the line through (0,4) perpendicular to the line y = 3x
Rufina [12.5K]

Answer:

y =  -  \frac{1}{3} x + 4

Step-by-step explanation:

The equation of a line is usually written in the form of y=mx+c, where m is the gradient and c is the y-intercept.

The product of the gradients of perpendicular lines is -1.

Gradient of given line= 3.

(Gradient of line)(3)= -1

3m= -1

m= -  \frac{1}{3}

subst. m= -  \frac{1}{3} into the equation:

y =  -  \frac{1}{3} x + c

To find the value of c, substitute a coordinate.

When x=0, y=4,

4 =  -  \frac{1}{ 3} (0) + c \\ 4 = c \\ c = 4

Thus the equation of the line is y =  -\frac{1}{3} x + 4.

3 0
3 years ago
A middle school campus is shaped like a rectangle with a width of 1/4 mile and a length of 1/2 mile. A map of the campus has a w
igomit [66]

Answer:

A) 1:4

Step-by-step explanation:

#We first calculate the campus' area:

a=lw\\\\=\frac{1}{4}\times \frac{1}{2}\\=0.125 \ mi^2

#We then calculate the campus' map area in square ft:

A=lw\\\\=0.5 \times 1\\\\=0.5 ft^2

Ratio is a comparison between two dimensions:

Ratio=\frac{0.125}{0.5}\\\\=0.25\\\\=\frac{1}{4}\\\\=1:4

Hence, the ratio of the area in square miles of the campus to the area in square feet of the map is 1:4

3 0
3 years ago
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