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Luda [366]
3 years ago
12

Consider the expression. (StartFraction 2 m Superscript negative 1 baseline n Superscript 5 Baseline Over 3 m Superscript 0 Base

line n Superscript 4 Baseline EndFraction) squared What is the value of the expression if m = –5 and n = 3? Negative StartFraction 24 Over 25 EndFraction Negative StartFraction 4 Over 25 EndFraction StartFraction 4 Over 25 EndFraction StartFraction 24 Over 25 EndFraction
Mathematics
2 answers:
suter [353]3 years ago
8 0

Answer:

The correct option is option (3) 4 ÷ 25.

Step-by-step explanation:

The expression in terms of <em>m</em> and <em>n</em> is:

F(m,n)=[\frac{2m^{-1}n^{5}}{3m^{0}n^{4}}]^{2}

Exponent rule of division:

a^{x}\div a^{y}=a^{x-y}

Compute the value of the expression for <em>m</em> = -5 and <em>n</em> = 3 as follows:

F(m,n)=[\frac{2m^{-1}n^{5}}{3m^{0}n^{4}}]^{2}

F(-5,3)=[\frac{2\csdot (-5)^{-1}\cdot (3)^{5}}{3\cdot (-5)^{0}\cdot (3)^{4}}]^{2}

             =\{\frac{2}{3}\times [(-5)^{-1-0}\times (3)^{5-4}}]\}^{2}\\\\=\{\frac{2}{3}\times \frac{-1}{5}\times 3\}^{2}\\\\=\{-\frac{2}{5}\}^{2}\\\\=\frac{4}{25}

Thus, the correct option is option (3) 4 ÷ 25.

Nata [24]3 years ago
6 0

Answer:

4/25

Step-by-step explanation:

I just did the test

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Answer:

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Step-by-step explanation:

Let's find the answer.

Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.

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From eq. 1 : 1 ; 2 ; 5

From eq. 2 : 1 ; 1 ; 1

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\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]

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\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]

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