First you simplify to 56x2 - 15x + 1.
Because of the 56, you know you will need a term with 8x and a term with 7x because 8*7=56. Answer C you can ignore because that won't give you a x^2, so it's between A and B.
The +1 in the simplified polynomial has to come from the multiplication of the numbers in the factorization. in A: -1*-1 = +1 but in B: +1*-1=-1 and that's not what we're looking for. So A is the correct answer.
13 percent * 5 years = 65
65% of the cheetah population will be lost in 5 years.
100 percent - 65 percent = 35.
35% of the cheetah population will remain in 5 years.
I do not see how this is a high school question, it's easy.
Answer:
Step-by-step explanation:
Pie 3.14
The length of rectangle is 44 yards and width of rectangle is 20 yards
<em><u>Solution:</u></em>
Let the length of rectangle be "a"
Let the width of rectangle be "b"
<em><u>Rectangle has a length that is 4 more than twice the width</u></em>
Length = 4 + 2(width)
Length = 4 + 2b
The perimeter is 128 yards
<em><u>The perimeter of rectangle is given by:</u></em>
Perimeter = 2(length + width)
128 = 2(4 + 2b + b)
128 = 2(4 + 3b)
Divide both sides by 2
64 = 4 + 3b
3b = 60
b = 20
<em><u>Substitute b = 20 in length</u></em>
Length = 4 + 2(20)
Length = 4 + 40 = 44
Thus length of rectangle is 44 yards and width of rectangle is 20 yards
Answer:
C = (2,2)
Step-by-step explanation:
B = (10 ; 2)
M = (6 ; 2)
C = (x ; y )
|___________|___________|
B (10;2) M (6;2) C ( x; y)
So:
dBM = dMC
√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 6)^2]
(2-2)^2 - (6-10)^2 = (y-2)^2 + (x - 6)^2
0 + (-4)^2 = (y-2)^2 + (x - 6)^2
16 = (y-2)^2 + (x - 6)^2
16 - (x - 6)^2 = (y-2)^2
Also:
2*dBM = dBC
2*√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 10)^2]
4*[(0)^2 + (-4)^2] = (y-2)^2 + (x - 10)^2
4*(16) = (y-2)^2 + (x - 10)^2
64 = (y-2)^2 + (x - 10)^2
64 = 16 - (x - 6)^2 + (x - 10)^2
48 = (x - 10)^2 - (x - 6)^2
48 = x^2 - 20*x + 100 - x^2 + 12*x - 36
48 = - 20*x + 100 + 12*x - 36
8*x = 16
x = 2
Thus:
16 - (x - 6)^2 = (y-2)^2
16 - (2 - 6)^2 = (y-2)^2
16 - (-4)^2 = (y-2)^2
16 - 16 = (y-2)^2
0 = (y-2)^2
0 = y - 2
2 = y
⇒ C = (2,2)