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iragen [17]
3 years ago
9

Mr. Scott times three fair coins. What is the probability that all three coins will land heads-up?

Mathematics
1 answer:
andrew-mc [135]3 years ago
6 0

Answer:

3.3333 repeating

Step-by-step explanation:

This is the answer because if you take 100 percent or just 100, and divide that by the number of coins there are ( which there are 3 in this case) then you would get your answer which is 3.3333 repeating...

Hope this answer helps

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nata0808 [166]
Mean is equal to sum/ number of values

27+3+2+25+5=62
62/5=12.4

Final answer: D, 12.4 years
5 0
2 years ago
Read 2 more answers
Can you please help me out
Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}

Hence, the best option is G.

5 0
1 year ago
A group of organs that work together together to perform a major function is called
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Answer:

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Anastasy [175]

Answer:

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x + x + y + y + 3y + 15

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2x +5y + 15

7 0
2 years ago
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