Answer:
The correct answer is 0.004
Step-by-step explanation:
I got it correct
Answer:
22
Step-by-step explanation:
The answer is y+61 or 61+y.
Hope it helps
You didn't include the formula.
Given that there is no data about the mass, I will suppose that the formula is that of the simple pendulum (which is only valid if the mass is negligible).
Any way my idea is to teach you how to use the formula and you can apply the procedure to the real formula that the problem incorporates.
Simple pendulum formula:
Period = 2π √(L/g)
Square both sides
Period^2 = (2π)^2 L/g
L = [Period / 2π)^2 * g
Period = 3.1 s
2π ≈ 6.28
g ≈ 10 m/s^2
L = [3.1s/6.28]^2 * 10m/s^2 =2.43 m
I hope this helps you.
Answer:
local calls per 1 long distance call.
Step-by-step explanation:
Local calls 
Long distance calls 
For 20 long distance calls local call ![=35 For 1 long distance calls local call [tex]=\frac{35}{20} =\frac{7}{4}](https://tex.z-dn.net/?f=%3D35%20%3C%2Fp%3E%3Cp%3EFor%201%20long%20distance%20calls%20local%20call%20%5Btex%5D%3D%5Cfrac%7B35%7D%7B20%7D%20%3D%5Cfrac%7B7%7D%7B4%7D)
