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Jlenok [28]
3 years ago
14

Need this very badly ​

Mathematics
1 answer:
Fofino [41]3 years ago
7 0
Can u show us how the location looks please?
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1) 448
aivan3 [116]

Answer:

What do I have to do?? I don't understand

3 0
3 years ago
step below. Question 1 Hexagon AGHBGHCGHD GHEGHFGH is a reflected image of hexagon ABCDEF. The midpoints of the sides of hexagon
Anuta_ua [19.1K]

Answer:

Hexagon AGHBGHCGHDGHEGHFGH coincides with hexagon ABCDEF when GH passes through the midpoints of opposite sides; that is, it is a perpendicular bisector of the two sides. HexagonAGHBGHCGHDGHEGHFGH also coincides with hexagon ABCDEF when the line of reflection joins a pair of vertices opposite one another on the hexagon. There are three perpendicular bisectors and three pairs of opposite vertices. In all, there are six lines of reflection that will map the hexagon back onto itself.

Step-by-step explanation:

5 0
3 years ago
Please answer
beks73 [17]

Answer:

(0,8)

Step-by-step explanation:

8 0
3 years ago
Consider this quadratic equation. 2x2 − 1 = 3x + 4 Which equation correctly applies the quadratic formula?
Mariulka [41]

Answer:

\frac{-(-3)+-\sqrt{(-3)^2-4(2)(-5)}}{2(2)}

Step-by-step explanation:

Quadratic formula: \frac{-b+-\sqrt{b^2-4ac} }{2a}

2x^2-1=3x+4\\\\2x^2-3x-5=0\\\\\\frac{-(-3)+-\sqrt{(-3)^2-4(2)(-5)}}{2(2)} \\\frac{3+-\sqrt{9+40} }{4}

x = \frac{3+-7}{4}

Hope this helps and God bless!

6 0
2 years ago
HELP!!!!!!!!!!!!!!!!!!!!
Alla [95]
No. The input a has multiple outputs
7 0
3 years ago
Read 2 more answers
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