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Klio2033 [76]
2 years ago
6

The line of reflection serves as the perpendiĉular bisector of the segment that connects a point with its image point. (True or

false?) helpp
Mathematics
1 answer:
sdas [7]2 years ago
5 0
The correct answer is (perpendicular bisector)
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5,-30,180,-1,080 what are the two next numbers
Sedbober [7]

Answer: The next two numbers are 6,480, -38,880.

Step-by-step explanation:

The pattern is to multiply each consecutive term by (-6).  Understand that a negative number times a positive number is a negative number (eg: 5 x - 6 = -30).

A negative number times a negative number is a positive number

(eg: -30 x -6 = 180).  Also, (-1,080 x -6 = 6,480.)  (6,480 x -6 = 38,880).

Hope this helps.

5 0
3 years ago
(3)-2<br> Evaluate exponent
olga nikolaevna [1]

Answer:

3^{-2} = \dfrac{1}{9}

Step-by-step explanation:

Definition of negative exponent:

a^{-n} = \dfrac{1}{a^n}

In our case, a = 3 and -n = -2.

3^{-2} = \dfrac{1}{3^2}

Now we just evaluate the power in the denominator.

3^{-2} = \dfrac{1}{3^2} = \dfrac{1}{9}

7 0
3 years ago
10x=5x2−1. Complete the square
vitfil [10]

Answer: I did the test too

4 0
1 year ago
there are n counters in a bag. 4 of the counters are red and the rest are blue. Ross takes a counter from the bag at random and
Ainat [17]

Answer: n = 10.

Step-by-step explanation:

In the bag, we have n counters.

4 of the counters are red.

the rest are blue, then we have:

(n - 4) blue counters.

Now, the probability that Ross takes a blue counter from the bag is equal to the quotient between the number of blue counters (n - 4) and the total number of counters, n

Then the probability is:

p1 = (n - 4)/n

Now he draws another, and it must be blue again, then we can calculate the probability in the same way as above, but he already take a blue counter, so the number of blue counters is (n - 5) and the total number of counters is (n - 1)

The probability of this event is:

p2 = (n - 5)/(n - 1)

The joint probability (the probability that Ross takes two blue counters) is equal to the product of the individual probabilities, and we know that this is equal to 1/3, then we have the equation:

1/3 = ( (n - 4)/n)*((n - 5)/(n - 1))

Now let's solve this for n.

n*(n - 1)/3 = (n - 4)*(n - 5)

(n^2 - n)/3 = n^2 - 4*n - 5*n + 20

n^2 - n = 3*(n^2 - 9*n + 20)

n^2 - n = 3*n^2 - 27*n + 60

0 = (3*n^2 - n^2) - 27*n + n + 60

0 = 2*n^2 - 26*n + 60

The two solutions of this equation can be found with Bhaskara's equation:

n = \frac{-(-26) +- \sqrt{(-26)^2 - 4*2*60} }{2*2} = \frac{26+- 14}{4}

Then the two solutions are:

n = (26 - 14)/4 = 3

This is not an option, because we know for sure that we have 4 red counters, then this option can be discarded.

The other solution is:

n = (26 + 14)/4 = 40/4 = 10

Then we have n = 10, 10 counters in total.

4 0
3 years ago
Pls help I dont understand. Find the inverse of this function.
lisov135 [29]

In the inverse we replace the place of x by y .

g(x) =  \sqrt[3]{x}  - 3 \\  \\ x =  \sqrt[3]{y}  - 3 \\  \sqrt[3]{y}  = x + 3 \\ y =  {(x + 3)}^{3}  \\ y =  {(x + 3)}^{2} (x + 3) \\ y =  ({x}^{2}  + 6x + 9)(x + 3) \\ \\  y =  {x}^{3}  + 6 {x}^{2}  + 9x + 3 {x}^{2}  + 18x + 27 \\  \\ y =  {x}^{3}  + 9 {x}^{2}  + 27x + 27 \\   \\ \\ g(x)^{ - 1}  =  {x}^{3}  + 9 {x}^{2}  + 27x + 27

I hope I helped you^_^

8 0
3 years ago
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