Answer:
Step-by-step explanation:
Write an equation for a line that is parallel to y + 5 = 3(x - 1) and goes through the point (3,-4)
1 answer:
Answer:
The equation for a line that is parallel to y + 5 = 3(x - 1) and goes through the point (3,-4) will be:
- y = 3x-13
Step-by-step explanation:
Given the equation
y + 5 = 3(x - 1)
Writing in the slope-intercept form
y=mx+b
where m is the slope and b is the y-intercept
y = 3(x-1) -5
y = 3x-3-5
y = 3x - 8
Thus, the slope = m = 3
We know that the parallel lines have equal slopes.
So, the slope of a parallel line is also 3
Using the point-slope form of the line equation
substituting the values m = 3 and the point (3, -4)
y-(-4)=3(x-3)
y+4 = 3x-9
y = 3x-9-4
y = 3x-13
Thus, the equation for a line that is parallel to y + 5 = 3(x - 1) and goes through the point (3,-4) will be:
- y = 3x-13
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Answer:
see explanation
Step-by-step explanation:
Given the 2 equations
A = x² + xy + 2y - 1 → (1)
A + B = 2x² - xy - 4y - 1 → (2)
From (2)
B = 2x² - xy - 4y - 1 - A
= 2x² - xy - 4y - 1 - (x² + xy + 2y - 1) ← distribute parenthesis
= 2x² - xy - 4y - 1 - x² - xy - 2y + 1 ← collect like terms
= x² - 2xy - 6y
Hence
A - B = x² + xy + 2y - 1 - (x² - 2xy - 6y) ← distribute parenthesis
= x² + xy + 2y - 1 - x² + 2xy + 6y ← collect like terms
= 3xy + 8y - 1
(b)
Given A - B = x, then
x = 3xy + 8y - 1 ( add 1 to both sides )
x + 1 = 3xy + 8y ← factor out y from each term
x + 1 = y(3x + 8) ← divide both sides by (3x + 8)
y =