Write an equation for a line that is parallel to y + 5 = 3(x - 1) and goes through the point (3,-4)
1 answer:
Answer:
The equation for a line that is parallel to y + 5 = 3(x - 1) and goes through the point (3,-4) will be:
- y = 3x-13
Step-by-step explanation:
Given the equation
y + 5 = 3(x - 1)
Writing in the slope-intercept form
y=mx+b
where m is the slope and b is the y-intercept
y = 3(x-1) -5
y = 3x-3-5
y = 3x - 8
Thus, the slope = m = 3
We know that the parallel lines have equal slopes.
So, the slope of a parallel line is also 3
Using the point-slope form of the line equation
substituting the values m = 3 and the point (3, -4)
y-(-4)=3(x-3)
y+4 = 3x-9
y = 3x-9-4
y = 3x-13
Thus, the equation for a line that is parallel to y + 5 = 3(x - 1) and goes through the point (3,-4) will be:
- y = 3x-13
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Put simply, you have to work backwards in making the equations. Start with the product of 8/3 and 9.
*9
Next take 1/4 of that. This can be done in two ways, either multiplying by 1/4:
(*9)*
, or dividing everything by 4.
(*9)/4
Finally, subtract three.
The final equation would read:
((*9)*)-3
Using PE(M/D)(A/S), we'd start with*9
3 and 9 cancel out to be 1 and 3, leaving us with
, or 8, and 3 and this part of the equation reading 8*3, which is 24.
The next step is
, which is 6.
Lastly we subtract 3 from six, leaving us 3.
Next take 1/4 of that. This can be done in two ways, either multiplying by 1/4:
(
, or dividing everything by 4.
(
Finally, subtract three.
The final equation would read:
((
Using PE(M/D)(A/S), we'd start with
3 and 9 cancel out to be 1 and 3, leaving us with
The next step is
Lastly we subtract 3 from six, leaving us 3.