Answer:
41.67% probability that a student has a dog given that they have a cat
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: having a cat.
Event B: having a dog.
12 of 27 students have a cat:
This means that 
5 students who have a cat and a dog.
This means that 
What is the probability that a student has a dog given that they have a cat?

41.67% probability that a student has a dog given that they have a cat
C. -2 because it is higher up in the negatives whereas -6 and -13 are lower even though the number seems greater
Answer:
[2×10*(-3) × (4×10*(4)] = 80
Step-by-step explanation:
First of all 0.002 is 10*(-3) and not 10(-2) , so you can eliminate the first 2 answers.
Second of all, according to the calculator the left equation is correct, while the right one isn't... so there you go
Glad to help :)
Step-by-step explanation:
try to impose the process of elimination and see if that helps