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Phantasy [73]
2 years ago
7

a storage jug was 4/5 full of water when did get indicated 72 what was the full capacity of the storage jug​

Mathematics
1 answer:
IRISSAK [1]2 years ago
6 0

Answer:

<em><u>9</u></em><em><u>0</u></em><em><u>. </u></em><em><u>(</u></em><em><u> </u></em><em><u>was </u></em><em><u>the </u></em><em><u>full </u></em><em><u>capacity</u></em><em><u> of</u></em><em><u> </u></em><em><u>jug</u></em><em><u>)</u></em>

<em><u>to </u></em><em><u>solve </u></em><em><u>this</u></em><em><u> </u></em>

<em><u>firstly</u></em><em><u> </u></em><em><u>let </u></em><em><u>the </u></em><em><u>full </u></em><em><u>capacity</u></em><em><u> </u></em><em><u>of </u></em><em><u>jug </u></em><em><u> </u></em>

<em><u> </u></em><em><u> </u></em>

<em><u>be</u></em><em><u>. </u></em><em><u>x</u></em>

<em><u>so,</u></em><em><u> </u></em>

<em><u>4</u></em><em><u>/</u></em><em><u>5</u></em><em><u>*</u></em><em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em><em><u>2</u></em>

<em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em><em><u>2</u></em><em><u>*</u></em><em><u>5</u></em><em><u>/</u></em><em><u>4</u></em>

<em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>9</u></em><em><u>0</u></em>

<em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em>

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Answer:

The coordinates of point A are (-11 , 2)

Step-by-step explanation:

- The coordinates of point P are (-31 , 8)

- The coordinates of point H are (29 , -10)

- Point E is the mid-point of segment PH

- The coordinates of the the mid-point are:

→ x=\frac{x_{1}+x_{2}}{2} and y=\frac{y_{1}+y_{2}}{2}

∵ E is the mid-point of segment PH

∴ The x-coordinate of point E is x=\frac{-31+29}{2}=-1

∴ The x-coordinate of point E is -1

∴ The y-coordinate of point E is y=\frac{8+-10}{2}=-1

∴ The y-coordinate of point E is -1

∴ The coordinates of point E are (-1 , -1)

- Point A is graphed \frac{2}{3} of the way along the segment from P to E

- That mean the distances from points P to A is 2 parts and from P to E

  is 3 parts, then the distance from A to E is "3 - 2" = 1 part

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→ x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}} and y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}

∵ Point A divides PE at ratio 2 : 1

∵ The coordinates of point P are (-31 , 8)

∵ The coordinates of point E are (-1 , -1)

∴ The x-coordinate of point A is x=\frac{(-31)(1)+(-1)(2)}{2+1}= -11

∴ The x-coordinate of point A is -11

∴ The y-coordinate of point A is x=\frac{(8)(1)+(-1)(2)}{2+1}=2

∴ The y-coordinate of point A is 2

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Step-by-step explanation:

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