Answer:
-0.9090... can be written as 
.
Explanation:
Any <em>repeating </em>decimal can be written as a fraction by dividing the section of the pattern to be repeated <em>by </em>9's.
We can start by listing out
0.909090... = 9/10 + 0/100 + 9/1000 + 0/10000 + 9/100000 + 0/1000000 + ...
Now. we let this series be equal to x, that is
= 9/10 + 0/100 + 9/1000 + 0/10000 + 9/100000 + 0/1000000 + ...
Now, we'll multiply both sides by 100
.
= 90 + 0 + 9/10 + 0/100 + 9/1000 + 0/10000 + ...
Then, subtract the 1st equation from the second like so:
= 90 + 0 + 9/10 + 0/100 + 9/1000 + 0/10000 + 9/100000 + 0/1000000 + ...
= - 9/10 - 0/100 - 9/1000 - 0/10000 - 9/100000 - 0/1000000 - ...
And we end up with this:
Finally, we divide both sides by 99 in order to isolate x and get the fraction we're looking for.
Which can be reduced and simplified to
Hope this helps!
Answer:
each number is the answer
Step-by-step explanation:
Answer:
y = -8
Step-by-step explanation:
Since the line is perpendicular to the y-axis, it will be a horizontal line that runs through (-4,-8).
When a line is perpendicular to the y-axis, the x-coordinate doesn't matter because the line will be horizontal, meaning it will be the same y value regardless of the x value. In this case, the y value is −8 throughout the line.
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8:5 x:7
8/5=x/7 Solve for x
x=11 1/5 or 11.2 liters
The graph of the linear equation can be seen in the image below.
<h3>
How to complete the table?</h3>
Here we have the linear equation:
y = -4x + 8
And we want to find 3 ordered pairs, to do so, we need to evaluate x in different values.
if x = 0 then:
y = -4*0 + 8 = 8
So we have the ordered pair (0, 8).
if x = 1 then:
y = -4*1 + 8 = 4
Then we have the ordered pair (1, 4)
If x = 2 then:
y = -4*2 + 8 = 0
Then we have the ordered pair (2, 0).
Now that we have these 3 ordered pairs, we can graph them in a coordinate axis and then connect them with a line, we will get something like the graph below.
That is the graph of our linear equation:
If you want to learn more about linear equations:
brainly.com/question/1884491
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