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Stella [2.4K]
3 years ago
9

CAN SOMEONE HELP ME PLEASE!!!

Mathematics
1 answer:
garik1379 [7]3 years ago
6 0
t^2 - 75 = 0

Add 75 to the other side to isolate the t^2

t^2 = 75

Take the square root of both sides to cancel out the t^2

\sqrt{t^2}  =   \sqrt{75}

t = 8.6602540

I'd round it.

t = 8.7
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How do you simplify 2^6? What do you get?
sertanlavr [38]

Answer:

64

Step-by-step explanation:

2*2*2*2*2*2

2 multiply 2 multiply 2 multiply 2 multiply 2 multiply 2.

7 0
2 years ago
Write a linear equation that passes through the two points (-6, -7) and (3, -4).
Phantasy [73]

linear equation that passes through the two points (-6, -7) and (3, -4) is y=\frac{1}{3}x-5

Step-by-step explanation:

We need to write the equation that passes through the two points (-6, -7) and (3, -4).

The equation can be written is point slope form.

The standard form of point slope equation is:

y=mx+b

where m is the slope and b is the y-intercept

Finding slope m:

Slope can be found by using formula:

slope = \frac{y_{2}-y_{1}}{x{2}-x_{1}} \\Where\,\, y_{2}=-4,y_{1}=-7,x{2}=3,x_{1}=-6\\slope =\frac{-4-(-7)}{3-(-6)}\\slope=\frac{-4+7}{3+6}\\slope=\frac{3}{9}\\slope=\frac{1}{3}

So, slope is \frac{1}{3}

Now finding y-intercept b

Putting slope \frac{1}{3} and point(-6,-7)

y=mx+b\\x=-6,y=-7,m=\frac{1}{3} \\-7=\frac{1}{3}(-6)+b\\-7=-2+b\\b=-7+2\\b=-5

So, value of b is -5

Putting values to find the equation:

y=mx+b\\m=\frac{1}{3} and b=-5\\y=\frac{1}{3}x-5

So, linear equation that passes through the two points (-6, -7) and (3, -4) is y=\frac{1}{3}x-5

Keywords: Linear Equation,

Learn more about Linear Equation at:

  • brainly.com/question/12954015
  • brainly.com/question/1979240
  • brainly.com/question/2601054

#learnwithBrainly

5 0
3 years ago
Construct a trapezium ABCD such that AD is parallel to BC, AB = 4.8 cm, BC = 6.8 cm, CD = 5.4 cm and ∠ABC = 60°. Measure and wri
lara31 [8.8K]

Answer:

AC = 6.05 cm

Step-by-step explanation:

We can draw two different trapeziums with the information given.

The possible drawings of the trapezium ABCD are in the image attached.

In both trapeziums, the length of AC is the same, and we can calculate this length using the law of cosines in the triangle ABC:

AC^2 = AB^2 + BC^2 - 2 * AB * BC * cos(B)

AC^2 = 4.8^2 + 6.8^2 - 2 * 4.8 * 6.8 * cos(60)

AC^2 = 23.04 + 46.24 - 65.28 * 0.5

AC^2 = 36.64

AC = 6.05 cm

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Debra drove 737 miles in 11 hours.
PSYCHO15rus [73]
It would take approximately 12.5 hours
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if the base area of a cylinder is 153.86 square centimeters and the height is 5 centimeters determine the volume of the cylinder
Natasha_Volkova [10]

Answer:

the answer is V≈769.3cm³

Step-by-step explanation:

7 0
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