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3 years ago

CAN SOMEONE HELP ME PLEASE!!!

Mathematics

1 answer:

garik1379 [7]3 years ago

6 0

$t^2 - 75 = 0$

Add 75 to the other side to isolate the $t^2$

$t^2 = 75$

Take the square root of both sides to cancel out the $t^2$

$\sqrt{t^2} = \sqrt{75}$

t = 8.6602540

I'd round it.

t = 8.7

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soldi70 [24.7K]

Answer:

yes

Step-by-step explanation:

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2 years ago

Evaluate,

kirill [66]

With 10 to the power to a negative number, it's easier.
Here's a trick: The negative number is the places to the right of the decimal. The last number is a 1, while the rest are 0s.

From this, we get: $10^{-4}=\boxed{0.0001}$

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2 years ago

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Determine whether the binomial is a factor of f(x).<br><br> f(x) = x3 + 11x2 + 24x - 36; x - 4

attashe74 [19]

If it is, then $f(4)$ would be equal $0$ .

$f(4)=4^3+11\cdot4^2+24\cdot4-36\\
f(4)=64+11\cdot16+96-36\\
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f(4)=300\not =0 \Rightarrow \text{ it isn't}$

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2 years ago

Based on the Nielsen ratings, the local CBS affiliate claims its 11:00 PM newscast reaches 41 % of the viewing audience in the a

ZanzabumX [31]

Answer:

1) Null hypothesis: $p\geq 0.41$

Alternative hypothesis: $p < 0.41$

2) $\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

3) $z_{crit}=-2.33$

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

4) $z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017$

5) $z_{crit}=-1.28$

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

6) We see that $|t_{calculated}|$ so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

7) Null hypothesis: $p\geq 0.41$

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

X represent the people indicated that they watch the late evening news on this local CBS station

$\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

$p_o=0.41$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v{/tex} represent the p value (variable of interest) Part 1We need to conduct a hypothesis in order to test the claim that 11:00 PM newscast reaches 41 % of the viewing audience in the area: Null hypothesis:[tex]p\geq 0.41$

Alternative hypothesis: $p < 0.41$

Part 2

$\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

Part 3

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.01 of the area on the left and on this case this value is :

$z_{crit}=-2.33$

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

Part 4

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017$

Part 5

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.1 of the area on the left and on this case this value is :

$z_{crit}=-1.28$

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

Part 6

We see that $|t_{calculated}|$ so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

Part 7

Null hypothesis: $p\geq 0.41$

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2 years ago

Cómo escribirias en multiplicación de factores primos el 600

Troyanec [42]

Multiplica fracciones: 600 × 3/5 = ? Resultado de la multiplicación de fracciones ordinarias (simples) explicado.

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3 years ago

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