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Stella [2.4K]
3 years ago
9

CAN SOMEONE HELP ME PLEASE!!!

Mathematics
1 answer:
garik1379 [7]3 years ago
6 0
t^2 - 75 = 0

Add 75 to the other side to isolate the t^2

t^2 = 75

Take the square root of both sides to cancel out the t^2

\sqrt{t^2}  =   \sqrt{75}

t = 8.6602540

I'd round it.

t = 8.7
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3 years ago
If one root of the equation is 4x^2- 2x+p-4 be the reciprocal of other. then find the value of p​
SashulF [63]

Answer:

p = 8

Step-by-step explanation:

Let one root of the eqn. be alpha . Other root is 1/alpha .

We know that product of both roots of an quadratic eqn. is c/a where "c" is the co-efficient of the constant  & "a" is the co-efficient of x^2.

Here "c" is p-4 & "a" is 4. And the product of roots is 1 ( ∵ prdouct of a number and its reciprocal is 1 )

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The general form of a circle is given as x^2+y^2+4x - 12y + 4 = 0. A) What are the coordinates of the center of the circle? B) W
Alex_Xolod [135]

Answer:

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radius = 6

Step-by-step explanation:

<u>Equation of a circle</u>

(x-a)^2+(y-b)^2=r^2

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Therefore, we need to rewrite the given equation into the standard form of an equation of a circle.

Given equation:

x^2+y^2+4x-12y+4=0

Collect like terms and subtract 4 from both sides:

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Complete the square for both variables by adding the square of half of the coefficient of x and y to both sides:

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2 years ago
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Read 2 more answers
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