Answer:se muestran los documentos recientes, la de iTunes muestra links para abrir la iTunes Store o reproducir toda nuestra colección, etc
Explanation:
Answer:
See attached for answer and explanation
Explanation:
Note: the question is incomplete, consider the statements below as the statements to be expressed in terms of C(x), D(x), F(x), quantifiers, and logical connectives.
(a) A student in your class has a cat, a dog, and a ferret.
(b) All students in your class have a cat, a dog, or a ferret.
(c) Some student in your class has a cat and a ferret, but not a dog.
(d) No student in your class has a cat, a dog, and a ferret.
(e) For each of the three animals, cats, dogs, and ferrets, there is a student in your class who has this animal as a pet.
Answer:
Hi there! Please find the answer below.
Explanation:
The program below demonstrates how each of the requirements can be coded in a simple Python script. To copy the array, we can use the copy() method of the array. To calculate the diff, we can use a few different techniques, so I have implemented it using a loop over the arrays and just storing and displaying the difference in the 2 arrays.
new_string.py
def add_test_score(score):
test_score.append(score);
contact_hash = {}
test_score = []
print("Enter 5 test scores: ");
for x in range(0, 5):
input_string = input("Enter test score " + str(x + 1) + ": ")
add_test_score(int(input_string));
print(test_score);
test_score_copy = test_score.copy();
for e in test_score_copy:
if e < 60:
test_score_copy[test_score_copy.index(e)] += 10;
diff = [];
for e in test_score:
print(test_score[test_score.index(e)]);
print(test_score_copy[test_score.index(e)]);
if not test_score[test_score.index(e)] == test_score_copy[test_score.index(e)]:
diff.append(e);
print(diff);
I’m not sure but I think it belongings.
<span>Determining the keystrokes of opening the cmos editor depends on the ram contained in the parameters in BIOS.It can be a very daunting task however made more accessible by instructions detailed in various ways by others.Research is needed.</span>