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allochka39001 [22]
2 years ago
12

What do you think that private information like passwords pin number will be guarded or shared with the public? why?

Computers and Technology
1 answer:
konstantin123 [22]2 years ago
4 0

The private information like passwords pin number will be guarded or shared with the public because it gives the first line of defense where it can act against any form of unauthorized access to a person's computer and personal information.

<h3>Why should you use passwords to protect private information?</h3>

Passwords is known to be that factor that tends to give the first line of defense against any form of what we call illegal access to your computer and also that of one's personal information.

Note that the stronger a password of a person is, the more protected one can say that one's computer will be from any kind of hackers and malicious software.

Therefore one need to or one  should maintain the use of a strong passwords for all accounts that are present on your computer.

Hence, The private information like passwords pin number will be guarded or shared with the public because it gives the first line of defense where it can act against any form of unauthorized access to a person's computer and personal information.

Learn more about passwords from

brainly.com/question/17174600

#SPJ1

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A 'array palindrome' is an array which, when its elements are reversed, remains the same (i.e., the elements of the array are sa
tia_tia [17]

Answer:

Here is the JAVA program:

class Main {    

static boolean isPalindrome(int array[], int starting, int ending) {  /*a boolean method that takes an integer-valued array, and a pair of integers representing the starting and ending indexes of the portion of the array to be tested for being a palindrome */

   if (starting >= ending) {  //base case

       return true;     }  //returns true

   if (array[starting] == array[ending]) {  //recursive case

       return isPalindrome(array, starting + 1, ending - 1);     }  //calls isPalindrome recursively to find out palindrome

   else {  

       return false;    }  }  //returns false if array is not palindrome

 

   public static void main (String[] args) {  //start of main function

   int array[] = { 1,2,3,2,1};  //creates an array

   int size = array.length;   //computes the size of array

 System.out.print(isPalindrome(array, 0, size - 1));    } } //calls method to test array for being  a palindrome

Explanation:

The program works as follows:

array = { 1,2,3,2,1}

starting = 0

ending = size-1 = 5-1 = 4

if (starting >= ending) condition evaluates to false because starting i.e. 0 is not greater or equal to ending i.e. 4. So the program moves to the next if part

if (array[starting] == array[ending])

This becomes:

if (array[0] == array[4])

The element at 0th index is the first element of the array i.e. 1 and the element at 4th index of array is the last element of array i.e. 1. So both these elements are equal so the following statement executes:

return isPalindrome(array, starting + 1, ending - 1);

Now the starting and ending become:

starting+1 = 0+1 = 1

ending-1 = 3

if (starting >= ending) base condition evaluates to false because starting  is not greater or equal to ending. So the program moves to the next if part

if (array[starting] == array[ending])

This becomes:

if (array[1] == array[3])

The element at 1st index is 2 and the element at 3rd index of array is 2. So both these elements are equal so the following statement executes:

return isPalindrome(array, starting + 1, ending - 1);

Now the starting and ending become:

starting+1 = 1+1 = 2

ending-1 = 2

if (starting >= ending) base condition evaluates to true because starting  is  equal to ending. So the following statement executes:

       return true;    

This means the function returns true and this shows that array is a palindrome.

The screenshot of the program and its output is attached.

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Pros and cons of access to a wide range of online services when it comes to an individual's safety?
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Talk about cyber bullying but also all of the advancement and conviences of technology
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3 years ago
Write a function `has_more_zs` to determine which of two strings contains # more instances of the letter "z". It should take as
nekit [7.7K]

Answer:

// Method's name: has_more_zs

// Parameters are text1 and text2 to hold the two phrases to be tested

public static String has_more_zs(String text1, String text2) {

 // Create and initialize z1 to zero

 // Use z1 to count the number of zs in text1

 int z1 = 0;

 // Create and initialize z2 to zero

 // Use z2 to count the number of zs in text2

 int z2 = 0;

 

 //Create a loop to cycle through the characters in text1

 //Increment z1 by one if the current character is a 'z'

 int i = 0;

 while (i < text1.length()) {

  if (text1.charAt(i) == 'z' || text1.charAt(i) == 'Z') {

   z1 += 1;

  }

  i++;

 }

 //Create a loop to cycle through the characters in text2

 //Increment z2 by one if the current character is a 'z'

 

 i = 0; //Re-initialize i to zero

 

 while (i < text2.length()) {

  if (text2.charAt(i) == 'z' || text2.charAt(i) == 'Z') {

   z2 += 1;

  }

  i++;

 }

 

 

 //Using the values of z1 and z2, return the necessary statements

 if (z1 > z2) {

  return "The phrase '" + text1 + "'" + " has more occurences of z than the phrase " + "'" + text2 + "'";

 }

 else if (z1 < z1) {

  return "The phrase '" + text2 + "'" + " has more occurences of z than the phrase " + "'" + text1 + "'";

 }

 else if (z1 == z2) {

  return "The strings have the same number of z";

 }

 else {

  return "Neither string contains the the letter z";

 }

}

Explanation:

Explanation to answer has been given in the code as comments. Please refer to the comments for the details of the code.

The source code file has been attached to this response and saved as "NumberOfZs.java"

Hope this helps!

Download java
5 0
3 years ago
50 Points being offered for the fastest and most correct response<br><br> How do I fix this?
kolezko [41]
Hi there!

Try resetting your browser, clearing your cache, and rebooting your computer.. If none of these work, or you've already tried these, let me know..

Hope this helps! ☺♥
5 0
3 years ago
Read 2 more answers
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