Organ viability is determined when a person is declared brain dead, so B.
The answer is firewall. It is a network security device that observes inbound and outbound network traffic and chooses whether to allow or block specific traffic based on a well-defined set of security rules. Firewalls have been a first line of protection in network security for over 25 years. The firewall present a barrier between measured and secured internal networks that can be trusted and untrusted outside networks, for example the Internet. A firewall can be software, hardware, or even both.
Answer:
Answered below
Explanation:
This solution is written in Kotlin programming language.
fun average (a: Int, b: Int, c: Int, d: Int, e: Int) : Double {
#variable to hold the addition of all parameters
var sum = a + b + c + d + e
#variable to hold the average of sum
var avg = sum / 5
return avg
}
#call the function to see how it works.
# this operation is done in the fun main()
var test: Double = average ( 5, 4, 7 , 3, 9)
print (test)
Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.
The video above uses the example
{
d
y
d
x
=
cos
(
x
)
y
(
0
)
=
−
1
to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you
y
=
sin
(
x
)
+
C
.
Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in
0
for
x
and
−
1
for
y
gives us
−
1
=
C
, meaning that the particular solution must be
y
=
sin
(
x
)
−
1
.
So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.
Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be
y
-values. Higher-order equations might have an initial value for both
y
and
y
′
, for example.
Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.
Explanation:
