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Vsevolod [243]
2 years ago
14

Write 95.491 as a mixed number​

Mathematics
2 answers:
Slav-nsk [51]2 years ago
7 0

Answer:

95 491/1000

Step-by-step explanation:

zhuklara [117]2 years ago
6 0

95.491 written as mixed number would look like: 95 491/1000

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If AB = 4 centimeters, which is closest to BC?
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Answer:

The correct answer AC = 11.52

Step-by-step explanation:

From the figure attached with this answer shows the triangle ABC.

BC=4 centimeters, m angle B=m angle c, and m angle a = 20 degrees

To find AC

From the figure we can see that D is the mid point and AD⊥BC

Then BD = CD = 4/2 = 2 cm

<BAD = 10° and <CAD = 10°

By using trigonometric ratio,

sin 10 = CD/AC = 2/AC

AC = 2/sin 10 = 2/0.1736 = 11.52

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A car can travel 105 miles on 7 gallons of gas. How far can it travel on 9 gallons
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Find how far the car can travel on one gallon of gas, by dividing total miles by number of gallons:

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Now multiply that by the number of gallons to find total miles:

15 miles per gallon x 9 gallons = 135 total miles.

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2 years ago
You have a handful of dimes and quarters that totals 26 coins and is worth $5.15. How many of each do you have?
borishaifa [10]

Answer:

9 dimes and 17 quarters

Step-by-step explanation:

9+17=26 coins

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Hope this helps! :)

5 0
2 years ago
Can you please help me out
Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}

Hence, the best option is G.

5 0
1 year ago
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