Step-by-step explanation:
a. 57×23=1311
b. 724×82=59368
c. (345)(210)=72450
a) The diagram shows that 16% of the students plays only the piano, 13% of the students plays only the violin, and 5% of the students plays both instruments.
So, the percentage of students playing the piano is 21%, because you can choose a students who plays only the piano (16%) or a student who plays both instruments (5%)
b) We can't answer this question without knowing the number of students in the school. In fact, we only know that 5% of the students plays both instrument. This means that, if the total number of students is
, the number of students who play both instruments is
![\dfrac{5x}{100}=\dfrac{x}{20}](https://tex.z-dn.net/?f=%5Cdfrac%7B5x%7D%7B100%7D%3D%5Cdfrac%7Bx%7D%7B20%7D)
And it is impossible to evaluate this quantity without knowing the value for x.
c) Since the probability of N is 21% (see point a), the probability of not N will be ![100-21 = 79](https://tex.z-dn.net/?f=100-21%20%3D%2079)
d) By the same logic, the probability of V is
percent. So, we have
![P(N\cup V) = P(N)+P(V)-P(N\cap V) = 0.21+0.18-0.05=0.34](https://tex.z-dn.net/?f=P%28N%5Ccup%20V%29%20%3D%20P%28N%29%2BP%28V%29-P%28N%5Ccap%20V%29%20%3D%200.21%2B0.18-0.05%3D0.34)
e) We have
![P(\lnot N \cap \lnot V) = P(\lnot(N\cup V))](https://tex.z-dn.net/?f=P%28%5Clnot%20N%20%5Ccap%20%5Clnot%20V%29%20%3D%20P%28%5Clnot%28N%5Ccup%20V%29%29)
And we just computed the probability of
to be 0.34. So, we have
![P(\lnot(N\cup V))=1-0.34=0.66](https://tex.z-dn.net/?f=P%28%5Clnot%28N%5Ccup%20V%29%29%3D1-0.34%3D0.66)
5,500 millimeters= 0.0055 liters
This is -3x4 - 2x3 + 3x2 + 3x4 - 4x3 + x2 = -6x3 + 4x2
Its B
Answer:
2g+60>92
Step-by-step explanation: