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hodyreva [135]
3 years ago
13

In ΔBCD, the measure of ∠D=90°, the measure of ∠B=75°, and DB = 93 feet. Find the length of BC to the nearest tenth of a foot.

Mathematics
1 answer:
lara31 [8.8K]3 years ago
8 0

Answer:

89.8 feet

Step-by-step explanation:

In ΔBCD, the measure of ∠D=90°, the measure of ∠B=75°, and DB = 93 feet. Find the length of BC to the nearest tenth of a foot.

We would solve the above question using Sine rule

The formula is given as:

DB/sin D = BC/sin B

93/sin 90 = BC/sin 75

We cross multiply

sin 90 × BC = 93 × sin 75

BC = 93 × sin 75/sin 90

BC = 89.83 feet

Approximately BC = 89.8 feet

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Let numbers of books be 'b' and numbers of CDs be 'c'

We can set up two equations:
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When we have two equations in terms of two different variables; b and c, that we need to solve, then this becomes a simultaneous equation problem. 

First, rearrange Equation [1] to make either b or c the subject:
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b=20-c

Then we substitute b=20-c into Equation [2]
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