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Anettt [7]
3 years ago
6

Find the potential solution to the equation log4(2 – x) = log4(–5x – 18).

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
4 0
Log₄(2 – x) = log₄(–5x – 18).

Since the logs have the same basis (4) & are equal then:

(2 – x) = (–5x – 18).  . Now solve for x & you will find x = -5
USPshnik [31]3 years ago
4 0

the answer for this equation is: -5

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Joey has 5 collector stamps.He receives 3 more stamps each week that he completes community service hours.X=the number of weeks
kirza4 [7]

Answer:

Therefore the required equation is

Y=5+3X

Step-by-step explanation:

Given that , Joey has 5 collector stamps.

He gets 3 more stamps each week.

The number of week is X.

1st week he got 3 stamps

2nd week he got (3+3)=2.3 stamps

3rd week he got (3+3+3)=3.3 stamps

Stamp that he got=( the number of week ×3)

Therefore at end of Xth week he got =(X × 3) =3X stamps

Total number of stamps that collected after x week

=5+3X

Therefore the required equation is

Y=5+3X

6 0
3 years ago
How to find the perimeter of a right triangle using Pythagorean
dsp73

Answer:

12

Step-by-step explanation:

7 0
2 years ago
How do you fully reduce 40/56 to lowest terms?
vladimir2022 [97]
10/19. 40/4=10, and 56/4=19. therefore the answer is 10/19.
5 0
3 years ago
The height of a trapezoid can be expressed as x – 4, while the bases can be expressed as x + 4 and x + 9. if the area of the tra
AlexFokin [52]

Answer: 19 cm

<u>Step-by-step explanation:</u>

A_{trapezoid}=\frac{b_{1}+b_{2}}{2}*h

                99 = \frac{(x+4 + x+9}{2}*(x - 4)

                99 = \frac{(2x + 13}{2}*(x - 4)

              198 = (2x + 13)(x - 4)

              198 = 2x² + 5x - 52

                 0 = 2x² + 5x - 250

                 0 = 2x²- 20x + 25x - 250

                 0 = 2x(x - 10) + 25( x - 10)

                 0 = (2x + 25)(x - 10)

0 = 2x + 25     or        0 = x - 10

  -\frac{25}{2} = x      or          x = 10

Since length cannot be negative, -\frac{25}{2} can be disregarded

Larger base: x + 9  = 10 + 9   = 19

5 0
2 years ago
Read 2 more answers
Need to know the answer
loris [4]

Answer:

Please find attached the required graph of the equation, y = x² - 2·x - 8, created using MS Excel

Step-by-step explanation:

The given function required to be plot is y = x² - 2·x - 8

Therefore, the coordinates of the vertex of the parabola formed by the equation (h, k) is given as follows;

h = -(-2)/(2×1) = 1

k = 1² - 2×1 - 8 = -9

The coordinates of the vertex = (1, -9)

The roots of the equation is given when y = 0, as follows;

At the roots, we have;

x² - 2·x - 8 = 0

By factorizing, we get

x² - 2·x - 8 = (x - 4)·(x + 2) = 0

Therefore. the roots of the equation are;

x = 4, and x = -2

The coordinates of the roots are;

(4, 0), and (-2, 0)

Two other points can be found at when x = 3 and when x = 0 as follows;

When x = 3, we have;

y = 3² - 2×3 - 8 = -5

(3, -5)

When x  = 0, we have;

y = 0² - 2×0 - 8 = -8

(0, -8)

The five points are;

(1, -9), (4, 0), (-2, 0), (3, -5), (0, -8)

The graph of the equation created using MS Excel showing the five points is attached.

6 0
2 years ago
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