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lana66690 [7]
3 years ago
5

Can someone help me plz? I’ll reward points + brainalist

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
7 0

Answer:for the first one I’m unsure but think it’s b and for the second one its 38 inches

Step-by-step explanation:

The radius is just half the circumference

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Please help me out if possible.
Katena32 [7]

Answer:

C

Step-by-step explanation:

Plotting the points in a sketch quickly shows that the vertices are not at right angles to each other, thus excluding rectangle and square whose vertices are at right angles.

The best selection is a rhombus

5 0
4 years ago
I Really need help its due in about 1 min!
Leokris [45]

Answer:332

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Clarisvaudney tem 12 anos. Seu primo é 50% mais novo.Qual é a soma da idade dos dois?
Nitella [24]
The answer is 18.

12/2=6
6+12=18
8 0
3 years ago
The length of the famed fred's fence is 5 more than twice it's width if the perimeter of the fence is 510 feet find the dimensio
Sveta_85 [38]

Answer:

  • 83 1/3 ft wide
  • 171 2/3 ft long

Step-by-step explanation:

Let w represent the width of the area. Then 2w+5 represents the length. The perimeter is twice the sum of length and width:

  P = 2(L+W)

  510 = 2(2w+5 +w) . . substitute given values

  255 = 3w +5 . . . . . . divide by 2

  250 = 3w . . . . . . . . . subtract 5

  83 1/3 = w . . . . . . . . .divide by 3; the width of the area

  2w+5 = 171 2/3 . . . .  the length of the area

The fenced area is 83 1/3 ft wide and 171 2/3 ft long.

4 0
4 years ago
A round trip from Montreal to LA is 2,688 miles and takes an airline 9 hours and 20 minutes. Given the outbound trip is the same
Ksju [112]

Answer:

4.074 hours

Step-by-step explanation:

r =

The formula for speed = Distance × Time

Hence,

Let the outbound speed = r

return trip speed = r + 25x/100 = 125r/100 = 1.25r

Note that: 9 hours and 20 minutes = 9.167

Let t1 and t2 be the time taken to travel on way and return journey.

t1 + t2 = 9 hr 10 min = 9.167 hrs

Hence:

2688/r + 2688/1.25r = 9.167

LCM(1.25r)

(2688 × 1.25) + 2688 /1.25r= 9.167

3360 + 2688 = 9.167 × 1.25r

6048 = 11.45875r

r = 6048/11.45875

Outbound trip rl = 527.8062615904876mph

Return trip speed = r + 25x/100 = 125r/100 = 1.25r

= 1.25 ×

659.75782699mph

Time for return trip = Distance/Speed

= 2,688 miles/659.75782699mph/

= 4.0742222222 hours

Approximately = 4.074 hours

8 0
3 years ago
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