What is. 9 divided by 204

Mathematics

1 answer:

gulaghasi [49]3 years ago

8 0

Is that .9? or was that period mark accidental?

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Solve for a. a+(−1.3)=−4.5

Debora [2.8K]

The answer to it is -3.2 or -3 1/5

7 0

3 years ago

Factoring trinomials Select two for each

JulijaS [17]

Answer:

x² - 3x - 10 = (x - 5) (x + 2)

x² - 3x - 18 = (x + 3) (x - 6)

Step-by-step explanation:

x² - 3x - 10

x² + 2x - 5x - 10

x(x + 2) - 5(x + 2)

(x - 5) (x + 2)

x² - 3x - 18

x² - 6x + 3x - 18

x(x - 6) + 3(x - 6)

(x + 3) (x - 6)

-TheUnknownScientist

4 0

3 years ago

Select the correct answer. The volume of one of the Great Lakes is 3. 5 × 103 cubic kilometers. If there are 6. 3 × 107 fish in

valentinak56 [21]

The average number of fish per cubic kilometer is $1. 8 \times 10^4$ .

The correct option is B.

Given

The volume of one of the Great Lakes is 3.5 × 103 cubic kilometers.

The number of fish in the lake = 6. 3 × 107.

<h3>What is the average value?</h3>

The average is the middle value of the given data set and is calculated by adding up all the numbers and dividing the result by the total quantity of figures added.

The average number of fish per cubic kilometer is given by;

$\rm \text{The average number of fish per cubic kilometer}= \dfrac{Number \ of \ fish \ in \ lake}{Total \ volume \ of \ lake}$

Substitute all the values in the formula;

$\rm \text{The average number of fish per cubic kilometer}= \dfrac{Number \ of \ fish \ in \ lake}{Total \ volume \ of \ lake}\\\\ \text{The average number of fish per cubic kilometer}= \dfrac{6.3\times 10^7}{3.5\times 10^3}\\ \text{The average number of fish per cubic kilometer}= 1.8 \times 10^4$