All categories

3 years ago

ILL BRAINLIEST YOU PLEASE HELP ME

Mathematics

1 answer:

alisha [4.7K]3 years ago

8 0

Answer:

9.7

Step-by-step explanation:

$cos(59)=5/x\\\\x*cos(59)=5\\\\x=5/cos(59)\\\\$

x ≈ 9.7

You might be interested in

A parabola intersects the x-axis at x=3, and x=9.

jekas [21]

Answer:

dfghzdsiygfiyrgai fyguygjsgdhvfjhvSYdgf;uygsdflHGDvchgzlsjdhgSDljugfviygdsvgyljsgdcjheiasgddiabsicygehfUYFsdhtf78754

Step-by-step explanation:

48485498 eafhgvsuyf75445461e76f4djfvjfg\

the answer is in there somewhere

4 0

4 years ago

the science club sponsor is ordering caps and shirts for the boys and girls in the science club.There are 45 science club member

poizon [28]

The shirts because if the caps come in packs of 3 then there will have to be more cap packages than shirt packages

8 0

3 years ago

Read 2 more answers

Melissa said that each member of her group completed 5/12 foot of a tower for a garden display. There were 3 members in her grou

Setler [38]

A) 5/12×3=1 1/4 I know this for sure

4 0

3 years ago

Read 2 more answers

A store is having a sale all items are marked 30% off

zepelin [54]

Since you didn’t put the numbers to find the amount, I’ll teach you how to.. Once you have the decimal figure, multiply it by the number for which you seek to calculate the percentage

6 0

3 years ago

The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15 days. If 64 women are

shtirl [24]

Answer:

0.3569 is the probability that they have a mean pregnancy between 266 days and 268 days.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 268 days

Standard Deviation, σ = 15 days

We are given that the distribution of lengths of pregnancies is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$\displaystyle\frac{\sigma}{\sqrt{n}} = \frac{15}{\sqrt{64}} = \frac{15}{8}$

P(pregnancy between 266 days and 268 days)

$P(266 \leq x \leq 268) = P(\displaystyle\frac{266 - 268}{\frac{15}{8}} \leq z \leq \displaystyle\frac{268-268}{\frac{15}{8}}) = P(-1.0667 \leq z \leq 0)\\\\= P(z \leq 0) - P(z < -1.067)\\= 0.5000 - 0.1431 = 0.3569 = 35.69\%$

$P(266 \leq x \leq 268) = 35.69\%$

6 0

3 years ago