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3 years ago

Find the distance between the two points in simplest radical form. (1,0) and (-8,3)

Mathematics

1 answer:

SVEN [57.7K]3 years ago

7 0

Answer:

Step-by-step explanation:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\(1,0)\quad\implies\quad x_1=1\,,\ \ y_1=0\\\\(-8,3)\quad\implies\quad x_2=-8\,,\ \ y_2=3\\\\d=\sqrt{(-8-1)^2+(3-0)^2}= \sqrt{(-9)^2+3^2}=\sqrt{81+9}\\\\d=\sqrt{90}=\sqrt{9\cdot10}=\sqrt9\cdot\sqrt{10}=3\sqrt{10}\approx9.49$

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Answer:

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expeople1 [14]

<h3><u>Given</u>:-</h3>

$\rightarrow$ Radius(r) of sphere = 3m

$\rightarrow$ Volume of the sphere.

<h3><u>Formula Used</u>:-</h3>

$\rightarrow$ Volume of sphere = $\sf{\frac{4}{3}πr^3}$

<h3><u>Solution</u>:-</h3>

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2 years ago

What is 2/6 in simplest form

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9514 1404 393

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Step-by-step explanation:

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<em>Comment on the question</em>

The directive to "compare the volumes" does not tell anything about the sort of comparison you are expecting. We note that the expression x^3-x^2 is zero or less up to the point where x=1, so we wonder exactly what it is supposed to be modeling. Any real volume will not be negative.

For small values of x, the quadratic is quite a bit larger. However, we know the cubic will grow larger than any quadratic for large values of x. So, the comparison you get will depend on the domain of interest—which is not specified.

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